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5 x [(85 - 35 : 7) : 8 + 90] - 50
= 5 x [(85 - 5) : 8 + 90] - 50
= 5 x [80 : 8 + 90] - 50
= 5 x [10 + 90] - 50
= 5 x 100 - 50
= 500 - 50
= 450
\(5\times\left[\left(85-35:7\right):8+90\right]-50\\ =5\times\left[\left(85-5\right):8+90\right]-50\\ =5\times\left[80:8+90\right]-50\\ =5\times\left[10+90\right]-50\\ =5\times100-50\\ =500-50=450\)
5[(85 - 35 : 7) : 8 + 90] - 50
= 5[(85 - 5) : 8 + 90] - 50
= 5.[ 80 : 8 + 90] - 50
= 5.[ 10 + 90 ] - 50
= 5. 100 - 50
= 500 - 50
= 450
5[(85 - 35 : 7) : 8 + 90] - 50
= 5[(85 - 5) : 8 + 90] - 50
= 5.[ 80 : 8 + 90] - 50
= 5.[ 10 + 90 ] - 50
= 5. 100 - 50
= 500 - 50
= 450
\(5.\left[\left(85-35:7\right):8+90\right]\)
\(=5.\left[\left(85-5\right):8+90\right]\)
\(=5.\left(80:8+90\right)\)
\(=5.\left(10+90\right)\)
\(=5.100\)
\(=500\)
\(5\left[\left(85-35:7\right):8+90\right]\)
\(=5\left[\left(85-5\right):8=90\right]-50\)
\(=5\left[80:8+90\right]-50\)
\(=5\left[10+90\right]-50\)
\(=5.100-50\)
\(=450\)
\(2^3-5^3:5^2+12\cdot2^2=8-5+48=51\\ 5\left[\left(85-35:7\right):8+90\right]-5\cdot2^2\\ =5\left(80:8+90\right)-20=5\cdot100-20=480\)
a: \(2^3-5^3:5^2+12\cdot2^2\)
\(=8-5+48\)
\(=51\)
b: \(5\cdot\left[\left(85-35:7\right):8+90\right]-5\)
\(=5\cdot\left[10+90\right]-5\)
=495
a) 23.15 -[115-(12-5)2 ]
= 23.15 -[115-36]
= 8.15 -79
= 120-79
=41
b)5.[(85 - 35 : 7) :8 + 90 ] - 50
=5 .[80:8+90]-50
=5.100-50
=500-50
=450
c){[261 - ( 36-31)3.2 ]-9}.1001
={[261 - 125.2 ]-9}.1001
={[261 -250 ]-9}.1001
={11-9}.1001
=2.1001
=2002
d)3.102 - [1200 - ( 42 - 2.3)3]
=3.100-[1200 -(16-6)3 ]
=300-[1200-1000]
=300-200
=100
5 . [(85 - 35 : 7) : 80 + 90] - 50
= 5 . [(85 - 5) : 80 + 90] - 50
= 5 . [80 : 80 +90] - 50
= 5 . [1 + 90] - 50
= 5 . 91 - 50
= 455 - 50 = 405
5 [ ( 85 - 35 : 7 ) : 80 + 90 ] - 50
= 5 [ ( 85 - 5 ) : 80 + 90 ] - 50
= 5 [ 80 : 80 + 90 ] - 50
= 5 [ 1 + 90 ] - 50
= 5 . 91 - 50
= 455 - 50
= 405
=))
Tính:
5.(( 85 - 35 : (-7) + 90) +491
= 5. (( 85 + 5 +90) + 491
= 5. 180 + 491
= 900 + 491
= 1391
5 . [( 85 - 35 : 7 ) : 8 + 90] - 52.2
= 5 . [ ( 85 - 5 ) : 8 + 90 ] - 25 . 2
= 5 . [ 80 : 8 + 90 ] - 50
= 5 . ( 10 + 90 ) -50
=5 . 100 - 50
= 500 - 50
= 450
\(5.[(85-35:7):8+90]-5^{2}.2\)
`=5.[(85-5):8+90]-25.2`
`=5.(80:8+90)-50`
`=5.(10+90)-50`
`=5.100-50`
`=500-50=450`