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`A)2/3=x/60`
`=>40/60=x/60`
`=>x=40`
`B)-1/2=y/18`
`=>-9/18=y/18`
`=>y=-9`
`C)3/x=y/35=-36/84`
Mà `-36/84=(-3 xx 12)/(7 xx 12)=-3/7`
`=>3/x=-3/7`
`=>x=-7`
`y/35=-3/7=-15/35`
`=>y=-15`
`D)7/x=y/27=-42/54`
Mà `-42/54=(-7 xx 6)/(9 xx 6)=-7/9`
`=>7/x=-7/9`
`=>x=-9`
`y/27=-7/9=-21/27`
`=>y=-21`
\(\dfrac{4}{x}=\dfrac{y}{21}=\dfrac{28}{49}=\dfrac{28:7}{49:7}=\dfrac{4}{9}\\ Vậy:x=\dfrac{4.9}{4}=9\\ y=\dfrac{4.21}{9}=\dfrac{28}{3}\)
\(\dfrac{x}{2}=\dfrac{3}{y}\\ \Leftrightarrow x.y=2.3=6\\ Vậy:\left[{}\begin{matrix}\left(x;y\right)=\left(1;6\right)=\left(6;1\right)\\\left(x;y\right)=\left(2;3\right)=\left(3;2\right)\end{matrix}\right.\)
a,\(\dfrac{42}{54}\)=\(\dfrac{7}{x}\)
\(\dfrac{7}{9}\)=\(\dfrac{7}{x}\)
⇒x=9
b,\(\dfrac{x}{15}\)=\(\dfrac{-2}{3}\)
\(\dfrac{x}{15}\)=\(\dfrac{-10}{15}\)
⇒x=-10
a, \(\frac{42}{54}\)= \(\frac{7}{x}\)=> 42x=7.54 => x=\(\frac{7.54}{42}\)= 9. Vậy x=9 b, \(\frac{x}{15}\)= \(\frac{-2}{3}\)=> 3x= (-2).15 => x= \(\frac{\left(-2\right).15}{3}\)= -10. Vậy x=-10 c, \(\frac{x}{27}\)= \(\frac{-5}{9}\)=> 9x=(-5).27 => x\(\frac{\left(-5\right).27}{9}\)= -15 Thay x = -15 vào biểu thức ta có: \(\frac{-15}{27}\)= \(\frac{-45}{y}\)=> -15y= (-45).27 => y= \(\frac{\left(-45\right).27}{-15}\)=81 Vậy x=-15, y = -81 .KÍCH NKA PẠN
a) (x - 7)(x + 3) < 0
=> \(\hept{\begin{cases}x-7>0\\x+3< 0\end{cases}}\)hoặc \(\hept{\begin{cases}x-7< 0\\x+3>0\end{cases}}\)
=> \(\hept{\begin{cases}x>7\\x< -3\end{cases}}\)hoặc \(\hept{\begin{cases}x< 7\\x>-3\end{cases}}\)(loại)
Vậy -3< x < 7
b) xy + 3x - 7y = 21
=> x(y + 3) - 7(y + 3) + 21 = 21
=> (x - 7)(y + 3) = 0
=> \(\hept{\begin{cases}x-7=0\\y+3=0\end{cases}}\)
=> \(\hept{\begin{cases}x=7\\y=-3\end{cases}}\)
a)(x-7)(x+3)<0
=>\(\hept{\begin{cases}\orbr{\begin{cases}x-7>0\\x+3< 0\end{cases}}\\\orbr{\begin{cases}x-7< 0\\x+3>0\end{cases}}\end{cases}}\Rightarrow\hept{\begin{cases}\orbr{\begin{cases}x>7\\x< -3\end{cases}}\\\orbr{\begin{cases}x< 7\\x>-3\end{cases}}\end{cases}}\Rightarrow\hept{\begin{cases}x\in\varnothing\\x\in\left\{-2;-1;0;1;2;3;4;5;6\right\}\end{cases}}\)
a) 5(x+7) - 10 = 2^3 . 5
5(x+7 ) -10 = 8 . 5 = 40
5(x+7) = 40 + 10 = 50
x + 7 = 50 : 5 = 10
x = 10 - 7 = 3
a) Ta có: \(\left|x\right|=42\Rightarrow x=\pm42\)
Nếu x = 42 => A = 42 + 7 + 12 = 61
Nếu x = -42 => A = -42 + 7 + 12 = -23
b) \(\left|x\right|=9\Rightarrow x=\pm9\)
Nếu x = 9 và y = 14 => B = 27 - 9 + 14 = 32
Nếu x = -9 và y = 14 => B = 27 + 9 + 14 = 50
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\(x\ne3;y\ne-7\)
\(\Rightarrow x-3=\frac{42}{y+7}\Rightarrow x=\frac{42}{y+7}+3\)
x nguyên khi \(42:y+7\Rightarrow y+7=\left\{-42;-21;-14;-7;-6;-3;-1;1;3;6;7;14;21;42\right\}\)
Từ đó tìm ra y và x tương ứng