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\(=>\dfrac{43}{8}+x=-\dfrac{46}{3}+\dfrac{173}{24}=-\dfrac{65}{8}\)
\(=>x=-\dfrac{65}{8}-\dfrac{43}{8}=-\dfrac{27}{2}\)
x=-46/3 +173/24 -43/8
x= 368/24 + 173/24 -129/24
x=103/6
=>x(x^2-9/16)=0
=>x(x-3/4)(x+3/4)=0
=>x=0; x=3/4; x=-3/4
\(27< 3^{x-2}< 243\)
\(\Rightarrow3^3< 3^{x-2}< 3^5\)
\(\Rightarrow3^{x-2}=3^4\)
\(\Rightarrow x-2=4\)
\(\Rightarrow x=4+2=6\)
Vậy...
Ta có : 27 < 3x - 2 < 243
\(\Rightarrow\) 33 < 3x - 2 < 35
\(\Rightarrow\) 3x - 2 = 34
\(\Rightarrow\) x - 2 = 4
x = 4 + 2
x = 6
\(a,-\frac{9}{12}=-\frac{9:3}{12:3}=-\frac{3}{4}\)
\(\frac{-18}{-24}=\frac{\left(-18\right):\left(-6\right)}{\left(-24\right):\left(-6\right)}=\frac{3}{4}\)
\(-\frac{35}{70}=-\frac{35:35}{70:35}=\frac{1}{2}\)
\(-\frac{9}{27}=-\frac{9:9}{27:9}=-\frac{1}{3}\)
\(b,\frac{1313}{4242}=\frac{1313:101}{4242:101}=\frac{13}{42}\)
\(\frac{-353535}{-424242}=\frac{\left(-353535\right):\left(-70707\right)}{\left(-424242\right):\left(-70707\right)}=\frac{5}{6}\)
\(c,\frac{2^3\times4^3\times5^4}{8^2\times25^3\times7}=\frac{2^3\times4^3\times25^2}{8\times8^2\times25^2\times25\times7}\) ( 4^3 = 8^2 ; 5^4 = 25^2 )
\(=\frac{1}{25\times7}=\frac{1}{175}\)
\(a.\frac{-9}{-12}=\frac{-9:3}{-12:3}=\frac{-3}{-4}.\)
\(\frac{-18}{-24}=\frac{-18:6}{-24:6}=\frac{-3}{-4}\)
\(\frac{-35}{-70}=\frac{-35:35}{-70:35}=\frac{-1}{-2}\)
\(\frac{-9}{-27}=\frac{-9:9}{-27:9}=\frac{-1}{-3}\)
đk : x khác 2
\(\left(x-2\right)^2=-81\)( vô lí )
vì (x-2)^2 > =0 ; -81 < 0
Vậy ko có gtri x tm
cảm ơn;-;