Câu hỏi của Phan Bảo Châu

Question

(|x|-2011)^ (2+2008)×(2+2009)=-(2^3-3^2)^2009

Nguyễn Hồng Phúc · Accepted Answer

x=2012Câu trả lời: x=2012

Duc Nguyen · Answer

$\left(\left|x\right|-2011\right)^{\left(2+2008\right)}\cdot\left(2+2009\right)=-\left(2^3-3^2\right)^{2009}$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(8-9\right)^{2009}$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(-1\right)^{2009}$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(-1\right)$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=1$

$\left(\left|x\right|-2011\right)^{2010}=\dfrac{1}{2011}$

???Câu trả lời: $\left(\left|x\right|-2011\right)^{\left(2+2008\right)}\cdot\left(2+2009\right)=-\left(2^3-3^2\right)^{2009}$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(8-9\right)^{2009}$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(-1\right)^{2009}$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=-\left(-1\right)$

$\left(\left|x\right|-2011\right)^{2010}\cdot2011=1$

$\left(\left|x\right|-2011\right)^{2010}=\dfrac{1}{2011}$

???