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( 2x - 3y )2 = 4x2 - 12xy + 9y2
( 3√x - y )2 = 9x - 6y√x + y2 ( x ≥ 0 )
\(a)\)
\(4x^2-4x+1\)\(=\left(2x-1\right)^2\)
\(b)\)
\(\left(3x+2\right)\left(2-3x\right)\)\(=4-9x^2\)
\(c)\)
\(\left(x-3\right)\left(x^2+3x+9\right)\)\(=x^3-27\)
\(a,4x^2-4x+1=\left(2x\right)^2-2.2x.1+1=\left(2x-1\right)^2\)
\(b,\left(3x+2\right)\left(2-3x\right)=\left(2+3x\right)\left(2-3x\right)=2^2-\left(3x\right)^2\)
\(c,\left(x-3\right)\left(x^2+3x+9\right)=\left(x-3\right)\left(x^2+3x.1+3^2\right)=x^3-3^3\)
a) \(\left(x-3\right)^2+2\left(x-3\right)\left(x+2\right)+\left(x+2\right)^2\)
\(=\left(x-3+x+2\right)^2\)
\(=\left(2x-1\right)^2\)
Hằng đẳng thức: \(\left(a+b\right)^2=a^2+2ab+b^2\).
b) \(\left(x+5\right)^2-\left(2x+10\right)\left(x-6\right)+\left(x-6\right)^2\)
\(=\left(x+5\right)^2-2\left(x+5\right)\left(x-6\right)+\left(x-6\right)^2\)
\(=\left[\left(x+5\right)-\left(x-6\right)\right]^2\)
\(=11^2=121\)
Hằng đẳng thức: \(\left(a-b\right)^2=a^2-2ab+b^2\).
a.\(\left(x-3\right)^2+2\left(x-3\right)\left(x+2\right)+\left(x+2\right)^2\)
\(=\left[\left(x-3\right)+\left(x+2\right)\right]^2\)
\(=\left(x-3+x+2\right)^2\)
\(=\left(2x-1\right)^2\)
b.\(\left(x+5\right)^2-\left(2x+10\right)\left(x-6\right)+\left(x-6\right)^2\)
\(=\left(x+5\right)^2-2\left(x+5\right)\left(x-6\right)+\left(x-6\right)^2\)
\(=\left[\left(x+5\right)-\left(x-6\right)\right]^2\)
\(=\left(x+5-x+6\right)^2\)
\(9\left(x-3y\right)^2-25\left(2x+y\right)^2\)
\(=\left[3\left(x-3y\right)\right]^2-\left[5\left(2x+y\right)\right]^2\)
\(=\left(3x-9y\right)^2-\left(10x+5y\right)^2\)
\(=\left[3x-9y+10x+5y\right]\left[3x-9y-\left(10x+5y\right)\right]\)
\(=\left(13x-4y\right)\left(-7x-14y\right)\)
\(=-7\left(x+2y\right)\left(13x-4y\right)\)
9(x - 3y)² - 25(2x + y)²
= 3².(x - 3y)² - 5².(2x + y)²
= (3x - 9y)² - (10x + 5y)²
= (3x - 9y - 10x - 5y)(3x - 9y + 10x + 5y)
= (-7x - 14y)(13x - 4y)
= -7(x + 2y)(13x - 4y)
a) (x + 3)2 - 2(x + 3)(x - 2) + (x - 2)2
= (x + 3 - x + 2)2 = 52 = 25
b) (2x + 5)2 + 2(2x + 5)(3x - 1) + (3x - 1)2
= (2x + 5 + 3x - 1)2 = (5x + 4)2
\(2.\left(3+1\right).\left(3^2+1\right).\left(3^4+1\right)\)
= \(\left(6+2\right)\left(3^2+1\right)\left(3^4+1\right)\)
= \(\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)\)
= \(\left(3^4-1\right)\left(3^4+1\right)\)
= \(3^8-1\)
Chúc bạn học tốt !!!
Bài làm:
Ta có: \(\left(x+3\right)^2-9\left(y-3\right)^2\)
\(=\left(x+3\right)^2-\left[3\left(y-3\right)\right]^2\)
\(=\left[x+3-3\left(y-3\right)\right]\left[x+3+3\left(y-3\right)\right]\)
\(=\left(x+3-3y+9\right)\left(x+3+3y-9\right)\)
\(=\left(x-3y+12\right)\left(x+3y-6\right)\)
\(\left(x+3\right)^2-9\left(y-3\right)^2\)
\(=\left[x+3+3\left(x-3\right)\right].\left[x+3-3\left(x-3\right)\right]\)