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\(a,\dfrac{-3}{35}=\dfrac{-5}{7}\cdot\dfrac{3}{25}\\ b,\dfrac{-3}{35}=\dfrac{-2}{5}:\dfrac{14}{3}\)
a) \(\frac{7}{2}.\frac{-1}{10}\)
b)\(7:\left(-20\right)\)
c)\(\frac{7}{20}+\frac{-7}{10}\)
d)\(\frac{-1}{5}+\frac{-3}{20}\)
\(a)\)
\(\frac{-25}{16}=\frac{\left(-5\right).5}{4.4}=\frac{\left(-5\right).5.3}{4.4.3}=\frac{\left(-5\right).15}{12.4}=\frac{\left(-5\right)}{12}.\frac{15}{4}\)
\(b)\)
\(\frac{-25}{16}=\frac{\left(-25\right).4.5}{16.4.5}=\frac{\left(-4\right).25.5}{5.16.4}=\frac{\left(-4\right)}{5}.\frac{125}{64}=\frac{\left(-4\right)}{5}:\frac{64}{125}\)
a) Gọi số cần tìm là: `x` \(\left(x\in Q;x\ne0\right)\)
Ta có: \(-\dfrac{25}{16}=\dfrac{-5}{12}x\)
`=>` \(x=-\dfrac{25}{16}\div\dfrac{-5}{12}=\dfrac{15}{4}\)
Vậy \(-\dfrac{25}{16}=\dfrac{15}{4}.\dfrac{-5}{12}\).
b) Gọi số cần tìm là: \(y\) \(\left(y\in Q;y\ne0\right)\)
Ta có: \(-\dfrac{25}{16}=-\dfrac{4}{5}\div y\)
\(\Rightarrow y=-\dfrac{4}{5}\div\dfrac{-25}{16}=\dfrac{64}{125}\)
Vậy \(-\dfrac{25}{16}=-\dfrac{4}{5}\div\dfrac{64}{125}\).
a) Gọi số cần tìm là: x (x∈Q;x≠0)
Ta có: −2516=−512x
⇒
x=−2516÷−512=154
Vậy −2516=154.−512
.
b) Gọi số cần tìm là: y
(y∈Q;y≠0)
Ta có: −2516=−45÷y
⇒y=−45÷−2516=64125
Vậy −2516=−45÷64125
.
a: \(-\dfrac{8}{25}=\dfrac{-7}{10}\cdot\dfrac{16}{35}\)
b: \(-\dfrac{8}{25}=\dfrac{12}{5}:\dfrac{-15}{2}\)
Giải
a) Ta có : \(\frac{-25}{16}=\frac{-5}{12}.\frac{15}{4}\)
b) Ta có : \(\frac{-25}{16}=\frac{-4}{5}.\frac{64}{125}\)
a) \(\dfrac{-7}{20}=\dfrac{1}{5}.\dfrac{-7}{4}\) b) \(\dfrac{-7}{20}=\dfrac{-7}{40}:\dfrac{1}{2}\) c) \(\dfrac{-7}{20}=\dfrac{2}{5}+\dfrac{-3}{4}\) d) \(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)
a)\(\dfrac{-7}{20}=\dfrac{-7}{10}\times\dfrac{1}{2}\)
b)\(\dfrac{-7}{20}=\dfrac{-7}{40}\times\dfrac{1}{2}\)
c)\(\dfrac{-7}{20}=\dfrac{7}{20}+\dfrac{-7}{10}\)
d)\(\dfrac{-7}{20}=\dfrac{-1}{5}+\dfrac{-3}{20}\)
a) \(\frac{-3}{35}.\frac{-5}{7}=\frac{3}{48}\)
b) \(\frac{-3}{35}:\frac{-2}{5}=\frac{3}{14}\)
a) −335.−57=348
b) −335:−25=314