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a) 6 2010 : 6 10 = 6 2000
b) ( 3 8 . 3 16 ) : ( 3 7 . 3 14 ) = 3 24 : 3 21 = 3 3
c) ( 2 26 : 2 10 ) : ( 2 18 : 2 16 ) = 2 16 : 2 2 = 2 14
d) 25 3 : 125 = ( 25 . 25 . 25 ) : 5 3 = 5 6 : 5 3 = 5 3
a: \(125^5:25^3=5^{15}:5^6=5^9\)
b: \(27^6:9^3=3^{18}:3^6=3^{12}\)
c: \(4^{20}:2^{15}=2^{40}:2^{15}=2^{45}\)
d: \(24^n:2^{2n}=24^n:4^n=6^n\)
e: \(64^4\cdot16^5:4^{20}=2^{24}\cdot2^{20}:2^{40}=2^4\)
2:
a: n=5^4
=>n=625
b: n^3=125
=>n^3=5^3
=>n=5
c: 11^n=1331
=>11^n=11^3
=>n=3
Bài 1:
a) \(2\cdot3\cdot2\cdot3\cdot2\cdot3=2^3\cdot3^3=6^3\)
b) \(100\cdot100\cdot100=100^3=\left(10^2\right)^3=10^6\)
c) \(2x\cdot2x\cdot2x=\left(2x\right)^3=8x^3\)
d) \(2\cdot2^3\cdot2^5=2^{1+3+5}=2^9\)
e) \(3^{10}\cdot3^5\cdot3^4=3^{10+5+4}=3^{19}\)
Bài 2:
\(40-x=2^6\cdot2^2\)
\(\Rightarrow40-x=2^8\)
\(\Rightarrow40-x=256\)
\(\Rightarrow x=40-256\)
\(\Rightarrow x=-216\)
b) \(3^2\cdot3^x=81\)
\(\Rightarrow3^{2+x}=3^4\)
\(\Rightarrow2+x=4\)
\(\Rightarrow x=4-2=2\)
c) \(2^x=512\)
\(\Rightarrow2^x=2^9\)
\(\Rightarrow x=9\)
d) \(x^5=243\)
\(\Rightarrow x^5=3^5\)
\(\Rightarrow x=3\)
Bài 3:
a) \(3^6=3\cdot3\cdot3\cdot3\cdot3\cdot3=729\)
b) \(8^3=\left(2^3\right)^3=2^9=512\)
c) \(3^3\cdot75+3^3\cdot25=3^3\cdot\left(75+25\right)=3^3\cdot100=27\cdot100=2700\)
d) \(2^3\cdot3-\left(1^{10}+8\right):3=2^3\cdot3-9:3=2^3\cdot3-3\cdot3:3=3\cdot\left(2^3-3:3\right)=3\cdot\left(8-1\right)=21\)
e) \(32-\left[4+\left(5\cdot3^2-42\right)\right]-14=18-\left[4+\left(45-42\right)\right]\)
\(=18-\left(4+3\right)\)
\(=18-7=11\)
2:
a: =>40-x=256
=>x=40-256=-216
b: =>x+2=4
=>x=2
c: =>2^x=2^9
=>x=9
d; =>x^5=3^5
=>x=3
a) \(4^9:4^4\)
\(=4^{9-4}\)
\(=4^5\)
b) \(17^8:17^5\)
\(=17^{8-5}\)
\(=17^3\)
c) \(2^{10}:8^2\)
\(=2^{10}:\left(2^3\right)^2\)
\(=2^{10-6}\)
\(=2^4\)
d) \(18^{10}:3^{10}\)
\(=\left(18:3\right)^{10}\)
\(=6^{10}\)
e) \(27^5:81^3\)
\(=\left(3^3\right)^5:\left(3^4\right)^3\)
\(=3^{15}:3^{12}\)
\(=3^{15-12}\)
\(=3^3\)
f) \(10^6:100\)
\(=10^6:10^2\)
\(=10^{6-2}\)
\(=10^4\)
g) \(5^9:25^3\)
\(=5^9:\left(5^2\right)^3\)
\(=5^9:5^6\)
\(=5^{9-6}\)
\(=5^3\)
h) \(4^{10}:64^3\)
\(=4^{10}:\left(4^3\right)^3\)
\(=4^{10-9}\)
\(=4\)
i) \(2^{25}:32^4:18^4:9^4\)
\(=\left(2^{25}:2^{20}\right):\left(18^4\cdot9^4\right)\)
\(=2^5:9^8:2^4\)
\(=2:9^8\)
\(=\dfrac{2}{9^8}\)
a)215+((-38)-(-58))+(90-85)
215+20+5
(215+5)+20
220+20
240
a,ƯCLN (42,58)=4
b,ƯCLN (156,13)=13
c,ƯCLN (90,150) =5
d,ƯCLN (215,205)=5
e,ƯCLN (85,161) =k có phần tử nào
j,ƯCLN (18,30,42)=6
g,ƯCLN (26,39.48)=k có phần tử nào
chúc bạn học tốt
a) Ta có:
42 = 2.3.7
58 = 2.29
=> ƯCLN ( 42 , 58 ) = 2
b) Ta có:
156 = 2².3.13
13 = 13
=> ƯCLN (156, 13) = 13
c) Ta có:
90 = 2.3².5
150 = 2.3.5²
=> ƯCLN (90, 150) = 2.3.5 = 30
d) Ta có:
215 = 5.43
205 = 5.41
=> ƯCLN (215, 205) = 5
e) Ta có:
85 = 5.17
161 = 7.23
=> Không tìm được ƯCLN (85, 161)
j) Ta có:
18 = 2.3²
30 = 2.3.5
42 = 2.3.7
=> ƯCLN (18, 30, 42) = 2.3 = 6
g) Ta có:
26 = 2.13
39 = 3.13
48 = 2⁴.3
=> Không tìm được ƯCLN (26, 39, 48)
Mong bạn chấm điểm. Chúc bạn học tốt!^^
a. -20+5=-15
b. 7
c. 35 + (-4)= 31
d. -129-37+29-63= -100-100 = -200
e. 217 -315-117+215 =100-100=0
f. 15:(-3)+24:2 = -5 + 12 = 7
g. (-5).(-7)-3.(14)= 35 - 42 = -7
H. (-15)x(-129+29) = -15 x -100 =1500
i. 13 x (-125+25) =13 x -100 = -1300
k. 37(-135+35) = 37 x -100 = -3700
a) 274.93 = (92)4.93 = 98.93 = 911
b) 72018 : 7 = 72017
c) 420 : 40 = 420
d) (38.315) : ( 37.314) = 323 : 321 = 32
e) (215 : 210) : (218 : 215) = 25 : 23 = 22
f) ( 416. 42) : (420 :42)
g) 254 : 125
a) \(27^4.9^3=\left(3^3\right)^4.\left(3^2\right)^3=3^{12}.3^6=3^{12+6}=3^{18}\)
b) \(7^{2018}:7=7^{2018-1}=7^{2017}\)
c) \(4^{20}:4^0=4^{20}:1=4^{20}\)
d) \(\left(3^8.3^{15}\right):\left(3^7.3^{14}\right)=3^{8+15}:3^{7+14}=3^{23}:3^{21}=3^{23-21}=3^2\)
e) \(\left(2^{15}:2^{10}\right):\left(2^{18}:2^{15}\right)=\frac{2^{15-10}}{2^{18-15}}=\frac{2^5}{2^3}=2^{5-3}=2^2\)
f) \(\left(4^{16}.4^2\right):\left(4^{20}:4^2\right)=4^{16+2}:4^{20-2}=4^{18}:4^{18}=1\)
g) \(25^4:125=\left(5^2\right)^4:5^3=5^8:5^3=5^{8-3}=5^5\)