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24 tháng 7 2016
\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)
\(=\frac{-2}{6}=\frac{-1}{3}\)
8 tháng 7 2016
\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\frac{2^{10}.3^8-2^{10}.3^8.3}{2^{10}.3^8+2^{10}.3^8.5}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+6\right)}=\frac{-2}{6}=\frac{-1}{3}=-\frac{1}{3}\)
HV
1
5 tháng 3 2018
A=210.310-210.39/210.38+210.38.5
A=2^10.3^9(1.3-1.1)/2^10.3^8(1.1+1.1.5)
A=3.2/1.6
A=6/6=1
NV
Nguyễn Việt Lâm
Giáo viên
20 tháng 1
\(B=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}=\dfrac{-2}{6}=-\dfrac{1}{3}\)
NT
1
A
28 tháng 6 2018
\(B=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)\(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+3^8.2^8.2^2.5}\)\(\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+3^8.2^{10}.5}=\frac{2^{10}.\left(3^8-3^9\right)}{2^{10}\left(3^8+3^8.5\right)}\)
\(=\frac{3^8-3^9}{3^8+3^8.5}=\frac{3^8-3^8.3}{3^8\left(1+5\right)}=\frac{3^8\left(1-3\right)}{3^8\left(1+5\right)}=\frac{1-3}{1+5}=\frac{-2}{6}=\frac{-1}{3}\)
HH
2
AK
12 tháng 3 2018
Tử số : \(4^5.9^4-2.6^9\)
\(=\left(2^2\right)^5.\left(3^2\right)^4-2.2^9.3^9\)
\(=2^{10}.3^8-2^{10}.3^9\)
Mẫu số : \(2^{10}.3^8+6^8.20\)
\(=2^{10}.3^8+2^8.3^8.2^2.5\)
\(=2^{10}.3^8+2^{10}.3^8.5\)
\(=2^{10}.3^8.6\)
H
29 tháng 1 2023
\(=\dfrac{2.3^9.2^9-\left(2^2\right)^5.\left(3^2\right)^4}{2^{10}.3^7+3^7.2^7.2^3.5}\\ =\dfrac{2^{10}.3^9-2^{10}.3^8}{2^{10}.3^7+3^7.2^{10}.5}\\ =\dfrac{2^{10}.3^8\left(3-1\right)}{2^{10}.3^7\left(1+5\right)}\\ =\dfrac{3.2}{6}=\dfrac{6}{6}=1\)
4 tháng 1 2019
( 4^5.9^4+2.6^9) : (2^10.3^8-6^8.2) = \(\frac{4^5.9^4+2.6^9}{2^{10}.3^8-6^8.2}=\frac{\left(2^2\right)^5.\left(3^2\right)^4+2.6^9}{2^{10}.3^8-6^8.2}\)
= \(\frac{2^{10}.3^8+2.6^9}{2^{10}.3^8-6^8.2}=\frac{2\left(6^8.8\right)}{2.6^8}=\frac{6^8.8}{6^8}=8\)