Question

[Bae Jinyoung]

Tính:

a,\(\frac{\left(-5\right)^{60}.30^5}{15^5.5^{61}}\)b,\(\frac{\left(-3\right)^{10}.15^5}{25^3.\left(-9\right)^7}\)

Answer 1

[나 재민]

\(a)\frac{(-5)^{60}.30^5}{15^5.5^{61}}=\frac{(5.2.3)^5}{(5.3)^5.5}=\frac{5^5.2^5.3^5}{5^5.3^5.5} =\frac{2^5}{5}=\frac{32}{5}\)

\(b) \frac{(-3)^{10}.15^5}{25^3.(-9)^7}=\frac{(-3)^{10} .(3.5)^5}{(5^2)^3.[(-3).3]^7}=\frac{(-3)^{10}.3^5.5^5}{5^6.(-3)^7.3^7}=\frac{(-3)^3}{5.3^2}=\frac{-3}{5}\)

~ Hok tốt a~