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`#3107.101107`
A.
`-7 + x = -3`
`=> x = -3 - (-7)`
`=> x = -3 + 7`
`=> x = 4`
Vậy, `x = 4`
B.
`-456 - x = 723`
`=> x = -456 - 723`
`=> x = -1179`
Vậy, `x = -1179`
C.
`-124-312 + x = -415`
`=> -436 + x = -415`
`=> x = -415 - (-436)`
`=> x = -415 + 436`
`=> x = 21`
Vậy, `x = 21`
D.
`-214+512-(-163)-x=-768- (-423)`
`=> 298 - (-163) - x = -345`
`=> 298 + 163 - x = -345`
`=> 461 - x = -345`
`=> x = 461 - (-345)`
`=> x = 461 + 345`
`=> x = 806`
Vậy, `x= 806.`
a: x-7=-3
=>x=-3+7=4
b: -456-x=723
=>x=-456-723=-1179
c: -124-312+x=-415
=>x-436=-415
=>x=21
d: -214+512-(-163)-x=-768-(-423)
=>461-x=-345
=>x=461+345=806
a, | x + 3 | - 12 = | -5 |
x + 3 - 12 = 5
x + 3 = 5 + 12
x + 3 = 17
x = 17 - 3 = 14
b, 25 - ( x- 5 ) = 415 x ( 15 - 415 )
25 - ( x - 5 ) = 415 x ( - 400 )
25 - ( x - 5 ) = - 166000
x - 5 = 25 - ( - 166000)
x - 5 = 166025
x = 166025 + 5
x = 166030
CHÚC BẠN HỌC TỐT
a) 3x-17=x+3
3x-x=17+3
2x=20 =>x=10
b) |x-3|-12=|-5|
|x-3|=17
x-3=17 hoặc x-3=-17
nếu x-3=17 thì x=20
nếu x-3=-17 thì x=-14
c) 2,5-(x-5)=-415-(15-415)
2,5-(x-5)=-15
x-5=2,5+15
x-5=17,5 =>x=22,5
\(a)484+x=\left(-632\right)+\left(-548\right)\)
\(484+x=-1180\)
\(x=(-1180)-484\)
\(x=-1664\)
\(b)\left(-x\right)+\left(-62\right)+\left(-46\right)=-14\)
\(\left(-x\right)+\left(-62\right)=-14-\left(-46\right)\)
\(\left(-x\right)+\left(-62\right)=-14+46\)
\(\left(-x\right)+\left(-62\right)=32\)
\(\left(-x\right)=32-\left(-62\right)\)
\(\left(-x\right)=32+62\)
\(\left(-x\right)=94\)
\(\Rightarrow x=94\)
\(c)25+\left(x-5\right)=-415-\left(15-415\right)\)
\(25+\left(x-5\right)=-415-\left(-400\right)\)
\(25+\left(x-5\right)=-415+400\)
\(25+\left(x-5\right)=-15\)
\(x-5=-15-25\)
\(x-5=-40\)
\(x=-40+5\)
\(x=-35\)
\(542+\left(218-x\right)=735\)
\(\Rightarrow\)\(\left(218-x\right)=735-542\)
\(\Rightarrow\)\(218-x=193\)
\(\Rightarrow\)\(x=218-193\)
\(\Rightarrow\)\(x=25\)
a)3-[17-x]=289-325
[17-x]=3-(289-325)
[17-x]=3-(-36)
[17-x]=39
x=17-39
x=-22
b)25-[x+5]=-415-[15-415]
25-[x+5]=-415+400
25-[x+5]=-15
[x+5]=25+15
[x+5]=40
x=40-5
x=35
a ) \(4^{10}.8^{15}\)
\(=\left(2^2\right)^{10}.\left(2^3\right)^{15}\)
\(=2^{20}.2^{45}\)
\(=2^{65}\)
a)\(4^{10}.8^{15}=\left(2^2\right)^{10}.\left(2^3\right)^{15}=2^{2.10}.2^{3.15}=2^{20}.2^{45}=2^{65}\)
b)\(4^{15}.5^{30}=4^{15}.5^{2.15}=4^{15}.\left(5^2\right)^{15}=4^{15}.25^{15}=\left(4.25\right)^{15}=100^{15}\)
c)\(27^{16}.9^{10}=\left(3^3\right)^{16}.\left(3^2\right)^{10}=3^{3.16}.3^{2.10}=3^{48}.3^{20}=3^{68}\)
d)\(72^3.54^2=\left(8.9\right)^3.\left(27.2\right)^2=8^3.9^3.27^2.2^2=\left(2^3\right)^3.\left(3^2\right)^3.\left(3^3\right)^2.2^2=2^{3.3}.3^{2.3}.3^{3.2}.2^2\)
\(=2^9.3^6.3^6.2^2=2^{11}.3^{12}\)
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