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\(D=4\left(\frac{4}{1.5}+\frac{4}{5.9}+...+\frac{4}{201.205}\right)\)
\(D=4\left(\left(1-\frac{1}{5}\right)+\left(\frac{1}{5}-\frac{1}{9}\right)+...+\left(\frac{1}{201}-\frac{1}{205}\right)\right)\)
D=4[(1-1/205)
D=4.204/205
=>D=816/205
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li-ke cho mình nhé bn Cao Minh Hoàng
ta có
(X-1):4+1=50
=>X=195
Gọi tổng đó là S
S=42 /1.5+42/5.9+....+42/193.195
S=4(1-1/5+1/5-1/9+...+1/193-1/195)
S=4(1-1/195)
=> S=776/195
mik nha
\(A=\frac{2}{5\cdot9}+\frac{2}{9\cdot13}+...+\frac{2}{55\cdot59}\)
\(A=2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{55}-\frac{1}{59}\right)\)
\(A=2\left(\frac{1}{5}-\frac{1}{59}\right)\)
\(A=2\left(\frac{59}{295}-\frac{5}{295}\right)\)
\(A=2\cdot\frac{54}{295}\)
\(A=\frac{536}{295}\)
12.A= 1.5.12+5.9(13-1)+9.13(17-5)+13.17(21-9)+.....+97.101(105 - 93)
12.A = 1.5.12 + 5.9.13 -1.5.9 + 9.13.17- 5.9.13 +.....+ 97.101.105 -93.97.101
12.A = 1.5.12 -1.5.9 + 97.101.105
A = (1.5.12 -1.5.9 + 97.101.105):12 = 85725
\(\dfrac{2}{1.5}\)+\(\dfrac{2}{5.9}\)+\(\dfrac{2}{9.13}\)+.................+\(\dfrac{2}{2013+2017}\)
=\(\dfrac{1}{1}\)-\(\dfrac{1}{5}\)+\(\dfrac{1}{5}\)-\(\dfrac{1}{9}\)+\(\dfrac{1}{9}\)-\(\dfrac{1}{13}\)+...................+\(\dfrac{1}{2013}-\dfrac{1}{2017}\)
=\(\dfrac{1}{1}-\dfrac{1}{2017}\)
=\(\dfrac{2017}{2017}+\dfrac{-1}{2017}\)
=\(\dfrac{2016}{2017}\)