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\(\frac{3}{4}x\frac{4}{5}:\frac{3}{5}x\frac{6}{7}:\frac{1}{7}x\frac{5}{6}\)\(=\)\(\frac{3}{4}x\frac{4}{5}x\frac{5}{3}x\frac{6}{7}x\frac{7}{1}x\frac{5}{6}\)\(=\)\(\frac{3x4x5x6x7x5}{4x5x3x7x1x6}\)\(=\)\(\frac{\left(3\right)x\left(4\right)x\left(5\right)x\left(6\right)x\left(7\right)x5}{\left(3\right)x\left(4\right)x\left(5\right)x\left(6\right)x\left(7\right)x1}\)\(=\)\(\frac{5}{1}\)\(=\)\(5\).
a,3/7+4/5+4/7.
= ( 3/7 + 4/7 ) + 4/5
= 1 + 4/5
= 9/5
b,6/11+1/3+5/11
= ( 6/11 + 5/11 ) + 1/3
= 1 + 1/3
= 4/3
#hien#
\(\frac{4}{5}.\frac{3}{7}+\frac{4}{5}.\frac{6}{7}-\frac{4}{5}.\frac{4}{14}\)
\(=\frac{4}{5}.\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{14}\right)\)
\(=\frac{4}{5}.1\)
\(=\frac{4}{5}\)
= 51/20
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= 3/14
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= 4/7 - 2/7
= 2/7
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= 17/45
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= 2/3
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= 2 x 1/4
= 1/2
\(\frac{1}{6}+\frac{1}{14}+\frac{5}{7}\)
\(=\frac{5}{21}+\frac{5}{7}\)
\(=\frac{20}{21}\)
\(\frac{1}{3}+\frac{4}{5}+\frac{5}{7}\)
\(=\frac{17}{15}+\frac{5}{7}=\frac{194}{105}\)
tk tớ với
a; 60 \(\times\) (\(\dfrac{7}{12}\) + \(\dfrac{4}{15}\))
= 60 \(\times\) \(\dfrac{7}{12}\) + 60 \(\times\) \(\dfrac{4}{15}\)
= 35 + 16
= 51
(6 x 5 + 7 - 37) x ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= (30 + 7 - 37) x ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0 x ( 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10)
= 0
Bài 1:
a, \(\frac{1}{7}+3+\frac{5}{6}=\frac{1}{7}+\frac{3}{1}+\frac{5}{6}=\frac{6}{42}+\frac{126}{42}+\frac{35}{42}=\frac{167}{42}\)
b, \(\frac{4}{7}+\frac{5}{9}+4=\frac{4}{7}+\frac{5}{9}+\frac{4}{1}=\frac{36}{63}+\frac{35}{63}+\frac{252}{63}=\frac{323}{63}\)
= 4/5* (3/7+6/7-4/14)
=4/5*14/14
=4/5*1
=4/15
=4/5x(3/7+6/7-4/14)
=4/5x1
=1