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`@` `\text {Ans}`
`\downarrow`
`a,`
`3,27 - 4,15`
`= -0,88`
`b,`
`-5,5 + (-2,85)`
`= -5,5 - 2,85`
`= -8,35`
`c,`
`0,67 + 1,56`
`= 2,23`
`d,`
`7,86 + (-5,3)`
`= 7,86 - 5,3`
`= 2,56`
`e,`
`4,5 - (-9,5)`
`= 4,5 + 9,5`
`= 14`
`f,`
`0,5*1,5`
`= 0,75`
`i,`
`0,6 \div 1,5`
`= 0,4`
`k,`
`0,75 \div (-0,4)`
`= -1,875`
A= \(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{3}}\)
A= \(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{\frac{11}{3}\left(0,75+0,6-\frac{3}{7}-\frac{3}{13}\right)}\)
A=\(\frac{1}{\frac{11}{3}}\)
A= \(\frac{3}{11}\)
\(A=\frac{0,75+0,6+\frac{3}{7}}{2,75+2,2+\frac{11}{7}}=\frac{3.0,25+3.0,2+3.\frac{1}{7}}{11.0,25+11.0,2+11\frac{1}{11}}=\frac{3\left(0,25+0,2+\frac{1}{7}\right)}{11\left(0,25+0,2+\frac{1}{7}\right)}=\frac{3}{11}\)
\(A=\frac{0,75+0,6+\frac{3}{7}}{2,75+2,2+\frac{11}{7}}\)
\(=\frac{\frac{3}{4}+\frac{3}{5}+\frac{3}{7}}{\frac{11}{4}+\frac{11}{5}+\frac{11}{7}}\)
= \(\frac{3\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}\right)}{11\left(\frac{1}{4}+\frac{1}{5}+\frac{1}{7}\right)}\)
\(=\frac{3}{11}\)
\(\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{13}}=\frac{3\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}{11\left(0,25-0,2+\frac{1}{7}+\frac{1}{13}\right)}=\frac{3}{11}\)
\(0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}-2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}\\ =\left(0,75-0,6-2,75-2,2\right)+3\cdot\left(\dfrac{1}{7}+\dfrac{1}{13}\right)+11\cdot\left(\dfrac{1}{7}+\dfrac{1}{13}\right)\\ =\left(-4,8\right)+\left(3+11\right)\cdot\dfrac{20}{91}\\ =-4,8+14\cdot\dfrac{20}{91}\\ =-\dfrac{24}{5}+\dfrac{40}{13}\\ =-\dfrac{112}{65}\)