Question

[Hoàng kim]

Tính ( hợp lí nếu được )

a) 2^3 . 2 + 3^15 : 3^13 + 2020^0

b) 2^3 . 15 - [115 - (12 - 5)^2]

c) 3^2 . 75 + 25 . 3^2 - 2000^1

d) 2 . { 240 - [150 - ( 2^2 . 30 - 2^5 . 5)]}

Answer 1

[Nguyễn Việt Hoàng]

\(2^3\times2+3^{15}\div3^{13}+2020^0\)

\(=2^4+3^2+1\)

\(=16+9+1=26\)

Answer 2

[Nguyễn Việt Hoàng]

\(2^3\times15-[115-\left(12-5\right)^2]\)

\(=8\times15-\left(115-7^2\right)\)

\(=120-115+49\)

\(=5+49=54\)