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Question

tính hợp lí

$2\dfrac{6}{7}\times\left[\left(\dfrac{-7}{5}-\dfrac{3}{2}:\dfrac{-5}{-4}\right)+\left(\dfrac{3}{2}\right)^2\right]$

HT.Phong (9A5) · Accepted Answer

$2\dfrac{6}{7}\times\left[\left(\dfrac{-7}{5}-\dfrac{3}{2}:\dfrac{-5}{-4}\right)+\left(\dfrac{3}{2}\right)^2\right]$$=2\dfrac{6}{7}\times\left[\dfrac{-7}{5}-\dfrac{3}{2}\times\dfrac{4}{5}+\left(\dfrac{3}{2}\right)^2\right]$$=2\dfrac{6}{7}\times\left[\dfrac{-7}{5}+\dfrac{3}{2}\times\left(-\dfrac{4}{5}+\dfrac{3}{2}\right)\right]$$=2\dfrac{6}{7}\times\left(\dfrac{-7}{5}+\dfrac{3}{2}\times\dfrac{7}{5}\right)$ $=2\dfrac{6}{7}\times\dfrac{7}{5}\times\left(\dfrac{3}{2}-1\right)$$=\dfrac{20}{7}\times\dfrac{7}{5}\times\dfrac{1}{2}$$=\dfrac{20}{5}\times\dfrac{1}{2}\=\dfrac{10}{5}\
=2
$Câu trả lời: $2\dfrac{6}{7}\times\left[\left(\dfrac{-7}{5}-\dfrac{3}{2}:\dfrac{-5}{-4}\right)+\left(\dfrac{3}{2}\right)^2\right]$$=2\dfrac{6}{7}\times\left[\dfrac{-7}{5}-\dfrac{3}{2}\times\dfrac{4}{5}+\left(\dfrac{3}{2}\right)^2\right]$$=2\dfrac{6}{7}\times\left[\dfrac{-7}{5}+\dfrac{3}{2}\times\left(-\dfrac{4}{5}+\dfrac{3}{2}\right)\right]$$=2\dfrac{6}{7}\times\left(\dfrac{-7}{5}+\dfrac{3}{2}\times\dfrac{7}{5}\right)$ $=2\dfrac{6}{7}\times\dfrac{7}{5}\times\left(\dfrac{3}{2}-1\right)$$=\dfrac{20}{7}\times\dfrac{7}{5}\times\dfrac{1}{2}$$=\dfrac{20}{5}\times\dfrac{1}{2}\=\dfrac{10}{5}\
=2
$

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