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\(\frac{11}{25}\)x(-24,8) -\(\frac{11}{25}\)x 75,2 = \(\frac{11}{25}\)x(-24,8-75.2) = \(\frac{11}{25}\)x (-100) = -44
\(a,51+6-1-0,2=55,8\)
\(b,2511\times-24,8-2511\times75,2\)
\(=-24,8\times75,2=-100\)
\(=-251100\)
a, 51+6-1-0,2
=57-1;2
=55.8
b, 2511. -24,8 -2511.75,2
=2511.(-24,8 -75,2)
=2511.-100
=-251100
A=(-3/4+2/3).11/9+(-1/4+1/3):|-9/11|
\(=\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{9}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{11}{9}\)
\(=\frac{11}{9}\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)
\(=\frac{11}{9}\left(-1+1\right)\)
\(=\frac{11}{9}.0\)
=0
V kế 3V - Nđ 3V;1,5V
V kế 5V- nguồn 3v,1,5v
V kế 9v - nguồn 3v,6v
V kế 15v - nguồn 12v
\(A=\frac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}\)
\(=\frac{\left(2^2\right)^6.\left(3^2\right)^5+2^9.3^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{-2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}.\left(1+5\right)}{-2^{11}.3^{11}.\left(2.3+1\right)}\)
\(=\frac{2.6}{-3.7}=\frac{-4}{7}\)
\(\left(x-\frac{3}{5}\right)=\frac{2}{5}×-\frac{1}{3}\)
\(\left(x-\frac{3}{5}\right)=-\frac{2}{165}\)
\(x=-\frac{2}{165}+\frac{3}{5}\)
\(x=\frac{97}{165}\)
vậy \(x=\frac{97}{165}\)
\(x×\left(\frac{3}{7}+\frac{2}{3}\right)=\frac{10}{21}\)
\(x×\frac{23}{21}=\frac{10}{21}\)
\(x=\frac{10}{21}:\frac{23}{21}\)
\(x=\frac{10}{23}\)
vậy \(x=\frac{10}{23}\)
\(\left(x-\frac{3}{5}\right):\frac{-1}{3}=\frac{2}{5}\)
=> \(x-\frac{3}{5}=\frac{2}{5}\cdot\left(-\frac{1}{3}\right)=-\frac{2}{15}\)
=> \(x=-\frac{2}{15}+\frac{3}{5}=-\frac{2}{15}+\frac{9}{15}=\frac{7}{15}\)
\(\frac{3}{7}x-\frac{2}{3}x=\frac{10}{21}\)
=> \(\left(\frac{3}{7}-\frac{2}{3}\right)x=\frac{10}{21}\)
=> \(-\frac{5}{21}x=\frac{10}{21}\)
=> \(x=\frac{10}{21}:\frac{-5}{21}=\frac{10}{21}\cdot\frac{-21}{5}=-2\)
Hai bài của ☆luffy cute☆ đều sai hết , xem xét lại đi nhé
\(\frac{11}{25}\)\(\left(-24,8\right)-\frac{11.}{25}\)\(x75,2\)
\(\frac{11}{25}\)\(\left[\left(-24,8\right)-75,2\right]=\frac{11}{25}\)\(x\left(-100\right)=-44\)