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2,
a) \(315-\left(135-x\right)=215\)
\(\Rightarrow135-x=315-215\)
\(\Rightarrow135-x=100\)
\(\Rightarrow x=135-100\)
\(\Rightarrow x=35\)
b) \(x-320:32=25\cdot16\)
\(\Rightarrow x-10=5^2\cdot4^2\)
\(\Rightarrow x-10=20^2\)
\(\Rightarrow x-10=400\)
\(\Rightarrow x=410\)
c) \(3\cdot x-2018:2=23\)
\(=3\cdot x-1009=23\)
\(\Rightarrow3\cdot x=1032\)
\(\Rightarrow x=1032:3\)
\(\Rightarrow x=344\)
d) \(280-9\cdot x-x=80\)
\(\Rightarrow280-x\cdot\left(9+1\right)=80\)
\(\Rightarrow280-10\cdot x=80\)
\(\Rightarrow10\cdot x=280-80\)
\(\Rightarrow10\cdot x=200\)
\(\Rightarrow x=20\)
e) \(38\cdot x-12\cdot x-x\cdot16=40\)
\(\Rightarrow x\cdot\left(38-12-16\right)=40\)
\(\Rightarrow x\cdot10=40\)
\(\Rightarrow x=40:10\)
\(\Rightarrow x=4\)
a; \(\dfrac{9}{4}\) - \(\dfrac{-11}{4}\)
= \(\dfrac{9}{4}\) + \(\dfrac{11}{4}\)
= \(\dfrac{20}{4}\)
= 5
b; \(\dfrac{7}{8}\) - \(\dfrac{3}{-8}\) - \(\dfrac{1}{8}\)
= \(\dfrac{7}{8}\) + \(\dfrac{3}{8}\) - \(\dfrac{1}{8}\)
= \(\dfrac{7+3-1}{8}\)
= \(\dfrac{9}{8}\)
c; \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) - \(\dfrac{-1}{21}\)
= \(\dfrac{-5}{21}\) - \(\dfrac{25}{21}\) + \(\dfrac{1}{21}\)
= \(\dfrac{-5-25+1}{21}\)
= \(\dfrac{-29}{21}\)
Bài làm:
\(A=\frac{4^2}{15}.\frac{5^2}{24}.\frac{6^2}{35}.....\frac{20^2}{399}=\frac{4^2}{3.5}.\frac{5^2}{4.6}.\frac{6^2}{5.7}.....\frac{20^2}{19.21}=\frac{\left(4.5.6.....20\right)\left(4.5.6.....20\right)}{\left(3.4.5.....19\right)\left(5.6.7.....21\right)}=\frac{20.4}{3.21}=\frac{80}{63}\)
Học tốt!!!!
a: =35/17-18/17-9/5+4/5
=1-1=0
b: =-7/19(3/17+8/11-1)
=7/19*18/187=126/3553
c: =26/15-11/15-17/3-6/13
=1-6/13-17/3
=7/13-17/3=-200/39
1.
a) \(-\frac{15}{17}>-\frac{19}{21}\)
b)\(-\frac{13}{19}>-\frac{19}{23}\)
c)\(-\frac{23}{49}>-\frac{25}{47}\)
d)\(\frac{317}{633}>\frac{371}{743}\)
e)\(-\frac{24}{35}< -\frac{19}{30}\)
f)\(\frac{12}{17}< \frac{13}{18}\)
g) \(-\frac{17}{26}< -\frac{16}{27}\)
h) \(\frac{84}{-83}< -\frac{337}{331}\)
i) \(-\frac{1941}{1931}< -\frac{2011}{2001}\)
j) \(-\frac{1930}{1945}>-\frac{1996}{2001}\)
k) \(\frac{37}{59}< \frac{47}{59}\)
I) \(-\frac{25}{124}>-\frac{27}{100}\)
m) \(-\frac{97}{201}>-\frac{194}{309}\)
n) \(-\frac{189}{398}< -\frac{187}{394}\)
o) \(-\frac{289}{403}>-\frac{298}{401}\)
1. a, 35x67+35x33=35x100=3500
b,8x39x125=8x125x39=1000x39=39000
5. a, ( -15)-|-7|=(-15)-7=-18
b, |-15|-|18|=15-18=-3
X+(-72)=(-28)+(-72)=-100
1.thực hiện phép tính ( hợp lý nếu có thể)
a) 35. 67 + 35. 33 = 35 . ( 67 + 33 ) = 33 . 100 = 3300
b) 8.39.125 = ( 8 . 125 ) . 39 = 1000 . 39 = 39000
a) 3.(15 − 5)2 − 215: 213 = 3.10.2-215:213 = 60 - 1,00... = (bạn tự tính)
b) 2.(3.52 – 12) =2.(156-12)=2.144=288
c) 52 − 24 : 23 =52-1,043478261 =51,043478261
a )2340 : [5. 89 - (125 + 5 . 72) + 5 . 11]
= 2340 : [445-(125+360)+55]
= 2340 : [445-485+55]
= 2340:15
=156
b) 30: {20- [5 + (5 – 2 )2]}=30:{20-[5+3.2]}=30:{20-11}=30:9=3,(3)
a) (−7) + (− 5) =-12
b) 2013 + [ 340 + ( − 2013)]=2013+340+(-2013)=[2013+(-2013)]+340=0+340=340
a) (– 15) – | − 7 |; =-15-7=-22
b) | − 15| − | 18 | =15-18=-3
Tính giá trị của biểu thức: x + (−72), biết x = − 28.
Thay x=-28 vào x+(-72) ta được:
=> -28+(-72)=-100
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)
a. 215 - 5 + 10 = 210 + 10 = 220
b. 13 + (-17) = -4
c. 25 . 5 . 2014 . 4 . 2 = (25 . 4) . (5 . 2) . 2014 = 100 . 10 . 2014 = 1000 . 2014 = 2014000
đ. 24.35 + 76.35 - 500 = (24 + 76) . 35 - 500 = 100 . 35 - 500 = 3500 - 500 = 3000
e. 3 + 7 + 11 + 15 + ... + 399 + 403 = 406 . 101 : 2 = 20503