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`a, 4/9 + 2/5 + 5/9= (4/9 +5/9) + 2/5= 1 + 2/5= 5/5 + 2/5= 7/5`
`b, 6/13 + 5/8 + 7/13=(6/13 + 7/13) + 5/8=1+5/8= 8/8 + 5/8= 13/8`
`c, 5/11 + 6/25 + 66/121 = ( 5/11 + 66/121 ) + 6/25=1 + 6/25 = 25/25 + 6/25 = 31/25`
`d, 1/2 + 1/3 + 1/4 + 1/6 + 1/12 + 1/24= (1/2 + 1/4) +(1/3 + 1/6) + (1/12 + 1/24)= 3/4 + 1/2 + 1/8= 6/8 + 4/8 + 1/8= 11/8`
`@ yl`
nhóm các số có cùng mẫu với nhau rồi cộng ra
8/27+4/5+19/27+11/15=(8/27+19/27) + (4/5+11/15)
= 1+ (12/15+11/15)
= 1+ 1/8/15=2/8/15
12/13+2/7+8/13+6/13+5/7=(12/13+8/13+6/13) + (2/7+5/7)
= 2+ 1
=3
Ý a có thể bạn chép nhầm 4/5 rồi
`a: =(7/3-4/3)+11/5=16/5`
`b: =(18/13-5/13)+55/46=1+55/46=101/46`
`c: =27/25-4/9-2/25+5/9=(27/25-2/25)+(5/9-4/9)=1+1/9=10/9`
a. \(\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\dfrac{4}{5}\)= \(1+\dfrac{4}{5}=\dfrac{9}{5}\)
b. \(\left(\dfrac{6}{11}+\dfrac{5}{11}\right)+\dfrac{2}{15}=1+\dfrac{2}{15}=\dfrac{17}{15}\)
\(c.\left(\dfrac{9}{32}+\dfrac{21}{2}\right)+\dfrac{6}{13}=\left(\dfrac{9}{32}+\dfrac{336}{32}\right)+\dfrac{6}{13}=\dfrac{4677}{416}\)
\(d.\left(\dfrac{4}{9}+\dfrac{15}{27}\right)+\dfrac{2}{5}=1+\dfrac{2}{5}=\dfrac{7}{5}\)
Bài 2:
Số phần tiền mẹ còn lại là:
\(1-\dfrac{1}{2}-\dfrac{2}{5}=\dfrac{1}{10}\) số tiền lúc đầu
a,\(\frac{1}{5}\times\frac{2}{9}\div\frac{1}{15}\)
\(=\frac{1}{5}\times\frac{2}{9}\times15\)
\(=\left(\frac{1}{5}\times15\right)\times\frac{2}{9}\)
\(=3\times\frac{2}{9}\)
\(=\frac{2}{3}\)
b\(\frac{4}{15}\times\frac{7}{15}\times\frac{5}{4}\)
\(=\left(\frac{4}{15}\times\frac{5}{4}\right)\times\frac{7}{15}\)
\(=\frac{1}{3}\times\frac{7}{15}\)
\(=\frac{7}{45}\)
c,\(\frac{21}{23}\times\frac{5}{11}\times\frac{44}{?}\)
d,\(26\times\frac{13}{42}\div13\)
\(=\left(26\div13\right)\times\frac{13}{42}\)
\(=2\times\frac{13}{42}\)
\(=\frac{13}{21}\)
60x [7/12+4/15]
60x153/180
=9180/180
b 1/2x2/3x3/4x4/5x5/6x6/7x7/8x8/9=40320/4032
\(\dfrac{7}{5}+\dfrac{8}{5}+\dfrac{7}{2}+\dfrac{1}{2}+\dfrac{12}{13}+\dfrac{27}{13}=\dfrac{15}{5}+\dfrac{8}{2}+\dfrac{39}{13}=3+4+3=10\)
a) \(\dfrac{7}{5}+\dfrac{7}{2}+\dfrac{8}{5}+\dfrac{12}{13}+\dfrac{1}{2}+\dfrac{27}{13}=\left(\dfrac{7}{5}+\dfrac{8}{5}\right)+\left(\dfrac{7}{2}+\dfrac{1}{2}\right)+\left(\dfrac{12}{13}+\dfrac{27}{13}\right)\)\(=3+4+3=10\)