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\(\frac{15.\left(\frac{1}{616}.\frac{1}{6.16}.\frac{1}{6.16}\right)}{33.\left(\frac{1}{6.16}.\frac{1}{6.16}.\frac{1}{6.16}\right)}=\frac{15}{35}\)
\(A=\frac{\frac{3}{2}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}{\frac{33}{10}\left(\frac{1}{6}-\frac{1}{16}+\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}\right)}=\frac{\frac{3}{2}}{\frac{33}{10}}=\frac{3}{2}:\frac{33}{10}=\frac{5}{11}\)
Ta có:\(A=\frac{\frac{15}{6.16}+\frac{15}{16.26}+\frac{15}{26.36}}{\frac{33}{6.16}+\frac{63}{16.26}+\frac{93}{26.36}}\)
=>\(A=\frac{\left(\frac{1}{6.16}+\frac{1}{16.26}+\frac{1}{26.36}\right).15}{\frac{33}{6.16}+\frac{\frac{21}{11}.33}{16.26}+\frac{\frac{31}{11}.33}{26.36}}\)
=>\(A=\frac{\left(\frac{1}{6.16}+\frac{1}{16.26}+\frac{1}{26.36}\right).15}{\frac{21}{11}.\frac{31}{11}.33.\left(\frac{1}{6.16}+\frac{1}{16.26}+\frac{1}{26.36}\right)}\)
=>\(A=\frac{15}{\frac{21}{11}.\frac{31}{11}.33}\)
=>\(A=\frac{15}{\frac{1953}{11}}\)
=>\(A=\frac{55}{651}\)
Vậy \(A=\frac{55}{651}\)
bạn tính theo sai phân hữu hạng ý.rút tử ra ngoai để mẫu là 1
\(\frac{\frac{15+15+15}{6\cdot32}}{\frac{33+63+93}{6\cdot32}}=\frac{\frac{45}{216}}{\frac{63}{216}}=\frac{45}{63}=\frac{5}{7}\)
(tử mẩu đều có số giống nhau thì gạch nha)
\(B=\frac{1}{16}+\frac{6}{16.26}+\frac{6}{26.36}+...+\frac{6}{2006.2016}\)
\(B=\frac{1}{16}+6\left(\frac{1}{16.26}+\frac{6}{26.36}+...+\frac{6}{2006.2016}\right)\)
\(B=\frac{1}{16}+\frac{6}{10}\left(\frac{1}{16}-\frac{1}{26}+\frac{1}{26}-\frac{1}{36}+...+\frac{1}{2006}-\frac{1}{2016}\right)\)
\(B=\frac{1}{16}+\frac{6}{10}\left(\frac{1}{16}-\frac{1}{2016}\right)\)
\(B=\frac{1}{16}+\frac{6}{10}.\frac{125}{2016}\)
\(B=\frac{1}{16}+\frac{25}{672}\)
\(B=\frac{67}{672}\)