Question

[Nguyễn Phương Anh]

Tìm x:

\(\left(\frac{1}{3}+\frac{1}{6}\right)\cdot2^{x+4}-2^x=2^{13}-2^{10}\)

Answer 1

[.]

\(\left(\frac{1}{3}+\frac{1}{6}\right).2^{x+4}-2^x=2^{13}-2^{10}\)

\(\frac{1}{2}.2^x.2^4-2^x=8192-1024\)

\(2^x.8-2^x=7168\)

\(2^x\left(8-1\right)=7168\)

\(2^x.7=7168\)

\(2^x=7168\div7\)

\(2^x=1024\)

\(2^x=2^{10}\)

\(\Rightarrow x=10\)

Vậy \(x=10\).

Answer 2

[ミ★luffy☆mũ☆rơm★彡]

(1/3+1/6).2^x.2^4-2^x=8192-1024

(1/3+1/6).2^x.2^4-2^x=7168

1/2.2^x.2^4-2^x=7168

1/2.2^x.(2^4-1)=7168

1/2.2^x.(8-1)=7168

1/2.2^x.7=7168

1/2.2^x=7168:7

1/2.2^x=1024

      2^x=1024:1/2

     2^x=2048

2^x=2^11

x=11

vậy x=11