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PT
2
31 tháng 7 2016
C =22−3 x 4− x =12−3 x +104− x =3(4− x )4− x +104− x =3+104− x ... +199.100 ). x =201251 +201252 +. .... =12√3 (4+2√3√3+1+4−2√3√3−1 )=12√3 .4√3−4+6−2√3+4√3+4−6−2√3(√3−1)(√3+1).
2 tháng 7 2018
\(\frac{1}{4}+\frac{8}{9}< \frac{x}{36}< 1-\frac{3}{8}+\frac{5}{6}\)
\(=\frac{41}{36}< \frac{x}{36}< \frac{35}{24}\)
=>\(x=35< x< 41\)
EC
8 tháng 9 2016
\(\left(-\frac{2}{3}:-\frac{1}{3}\right).\left(-\frac{9}{2}\right)-\frac{1}{4}< \frac{x}{8}< -\frac{1}{2}.\frac{3}{4}:\frac{1}{8}+1\)
\(2.\left(-\frac{9}{2}\right)-\frac{1}{4}< \frac{x}{8}< \left(-3\right)+1\)
\(\left(-9\right)-\frac{1}{4}< \frac{x}{8}< \left(-2\right)\)
\(\left(-\frac{37}{4}\right)< \frac{x}{8}< \left(-2\right)\)
\(-\frac{74}{8}< \frac{x}{8}< -\frac{16}{8}\)
Vậy -74<x<-16
NH
1
17 tháng 9 2017
\(\frac{x-1}{9}+\frac{x-2}{8}+\frac{x-3}{7}=\frac{x-4}{6}\)
\(\frac{x-1}{9}+\frac{x-2}{8}+\frac{x-3}{7}-\frac{x-4}{6}=0\)
\(\frac{56.\left(x-1\right)}{504}+\frac{63.\left(x-2\right)}{504}+\frac{72.\left(x-3\right)}{504}-\frac{84.\left(x-4\right)}{504}=0\)
\(\frac{56x-56}{504}+\frac{63x-126}{504}+\frac{72x-216}{504}-\frac{84x-336}{504}=0\)
\(\Rightarrow56x-56+63x-126+72x-216-84x+336=0\)
\(\Rightarrow107x-62=0\)
\(\Rightarrow107x=62\)
\(\Rightarrow x=\frac{62}{107}\)
vay \(x=\frac{62}{107}\)
NT
Tìm x biết: \(\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}.\)
4
13 tháng 8 2017
\(\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}\)
\(\Rightarrow\frac{x+1}{9}+\frac{x+4}{6}+\frac{x+5}{5}+3=\frac{x+2}{8}+\frac{x+3}{7}+\frac{x+6}{4}+3\)
\(\Rightarrow\left(\frac{x+1}{9}+1\right)+\left(\frac{x+4}{6}+1\right)+\left(\frac{x+5}{5}+1\right)=\left(\frac{x+2}{8}+1\right)\)\(+\left(\frac{x+3}{7}+1\right)+\left(\frac{x+6}{4}\right)\)
\(\Rightarrow\frac{x+10}{9}+\frac{x+10}{6}+\frac{x+10}{5}=\frac{x+10}{8}+\frac{x+10}{7}+\frac{x+10}{4}\)
\(\Rightarrow\left(x+10\right)\left(\frac{1}{9}+\frac{1}{6}+\frac{1}{5}\right)=\left(x+10\right)\left(\frac{1}{8}+\frac{1}{7}+\frac{1}{4}\right)\)
\(\Rightarrow\left(x+10\right)\frac{43}{90}=\left(x+10\right)\frac{29}{56}\)
\(\Rightarrow x+10=0\)
\(\Rightarrow x=-10\)
S
13 tháng 8 2017
cộng 3 vào cả hai vế nên phương trình vẫn bằng nhau
Ta có \(\frac{x+1}{9}+1+\frac{x+4}{6}+1+\frac{x+5}{5}+1=\frac{x+2}{8}+1+\frac{x+3}{7}+1+\frac{x+6}{4}+1\)
\(\Leftrightarrow\frac{x+10}{9}+\frac{x+10}{6}+\frac{x+10}{5}=\frac{x+10}{8}+\frac{x+10}{7}+\frac{x+10}{4}\)
\(\Leftrightarrow\frac{x+10}{9}+\frac{x+10}{6}+\frac{x+10}{5}-\frac{x+10}{8}-\frac{x+10}{7}-\frac{x+10}{4}=0\)
\(\Leftrightarrow\left(x+10\right)\left(\frac{1}{9}+\frac{1}{6}+\frac{1}{5}-\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\right)=0\)
mà \(\frac{1}{9}+\frac{1}{6}+\frac{1}{5}-\frac{1}{8}-\frac{1}{7}-\frac{1}{6}\ne0\)
\(\Rightarrow x+10=0\)
\(\Leftrightarrow x=-10\)
T
5 tháng 6 2019
#)Giải :
a) x + 2x + 3x + ... + 100x = - 213
=> 100x + ( 2 + 3 + 4 + ... + 100 ) = - 213
=> 100x + 5049 = - 213
<=> 100x = - 5262
<=> x = - 52,62
T
5 tháng 6 2019
#)Giải :
b) \(\frac{1}{2}x-\frac{1}{3}=\frac{1}{4}x-\frac{1}{6}\)
\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{3}+\frac{1}{6}\)
\(\Rightarrow\frac{1}{2}x+\frac{1}{4}x=\frac{1}{2}\)
\(\Rightarrow\left(\frac{1}{2}+\frac{1}{4}\right)x=\frac{1}{2}\)
\(\Rightarrow\frac{3}{4}x=\frac{1}{2}\)
\(\Leftrightarrow x=\frac{2}{3}\)
TV
0
TB
0
\(\frac{x-1}{9}=\frac{8}{3}\Rightarrow\frac{x-1}{9}=\frac{8.3}{3.3}\Rightarrow\frac{x-1}{9}=\frac{24}{9}\Rightarrow\frac{x}{9}=\frac{24+1}{9}\Rightarrow\frac{x}{9}=\frac{25}{9}\Rightarrow x=25\)
\(\frac{x-1}{9}=\frac{8}{3}\)
\(x-1=\frac{8.9}{3}\)
\(x-1=\frac{72}{3}\)
\(x-1=24\)
\(x=24-1\)
\(x=23\)