Question

[Isabella]

Tìm x:

a, \(y+30\%y=-1,3\)                          b, \(y-25\%y=\frac{1}{2}\).         

c, \(3\frac{1}{3}y+16\frac{3}{4}=-13,25\)

Answer 1

[Phạm Văn An]

Tìm x mà biến y!

a) y + 30%y = -1,3

<=> 100%y + 30%y = -1,3

<=> 130% y= -1,3

=> y = -1,3: 130% = -1,3 x 100 : 130 = -1

b) ..... <=> 100% y - 25%y = 0,5

<=> 75% y = 0,5 => y = 0,5 : 75% = 0,5x100 : 75 = 2/3

c) ...<=> 10/3y + 16,75 = - 13,25

<=> 10/3y = -13,25 - 16,75

<=> 10/3 y = - 30

=> y = -30 : 10/3 = -9