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\(\Leftrightarrow\left[{}\begin{matrix}2x-1=3\\2x-1=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)
\(\Rightarrow\frac{4x^2-4x+1}{3}-\frac{3}{2}\left(x^2+6x+9\right)=\frac{1}{3}\left(x^2-1\right)+2x\)
\(\Rightarrow\frac{4x^2-4x+1}{3}-\frac{3x^2+18x+27}{2}=\frac{x^2-1}{3}+2x\)
\(\Rightarrow8x^2-8x+2-9x^2-54x-81=2x^2-2+12x\)
\(\Rightarrow-3x^2-74x-77=0\)
\(\Delta=5476-4.\left(-77\right).\left(-3\right)=4552\)
\(\Rightarrow\sqrt{\Delta}=\sqrt{4552}\)
\(\Rightarrow x=\frac{-74+\sqrt{4552}}{6};x=\frac{-74-\sqrt{4552}}{6}\)
\(\frac{\left(2x-1\right)^2}{3}-\frac{3.\left(x+3\right)^2}{2}=\frac{x^2-1}{3}+2x\)
Qui đồng lên là tìm được
(x-13)-25=(-1)-(-17)
<=>x-13-25=(-1)+17
<=>x-38=16
<=>x=16+38
<=>x=54
HT
a) 10 -2x = 25 -3x => -2x +3x = 25 -10 => x =15
b) 2.( |x+1| -3 ) -1 =7 =.> 2.( |x+1| -3) = 7+1 => 2 |x+1| -6 = 8 => 2 |x+1| = 8+6 => 2|x+1| =14=> |x+1| =7
+ x+1 =7 => x =6 hoặc x+1 =- 7 => x =-7 -1 =-8
c) | 2x-5| =7 => 2x -5 =7 => 2x =12 => x =6
hoặc 2x -5 = -7 => 2x = -2 => x =-1
=>(x . 3 -8)=7 . 4
=>x . 3-8 =28
=.x.3 = 28+8
=>x.3= 36
=>x=36:3
=>x=12
(x . 3 - 8):4 = 7
x.3 - 8 = 7 . 4 = 28
x.3 = 28 + 8 = 36
x = 36:3 = 12
a: \(\Leftrightarrow-\dfrac{4}{9}-\dfrac{2}{9}+\dfrac{2}{3}< =x< =\dfrac{11}{7}+\dfrac{3}{7}+\dfrac{2}{5}-\dfrac{7}{5}\)
=>0<=x<=2-1=1
hay \(x\in\left\{0;1\right\}\)
b: \(\Leftrightarrow-\dfrac{8}{13}+\dfrac{21}{13}+\dfrac{7}{17}< =x< =\dfrac{-9}{14}-\dfrac{5}{14}+3\)
=>24/17<=x<=2
hay x=2
\(5x+x=30\)
\(x\left(5+1\right)=30\)
\(6x=30\)
\(\Leftrightarrow x=5\)
\(8x+2x=100\)
\(x\left(8+2\right)=100\)
\(10x=100\)
\(x=10\)
a) 5x + x = 30
\(\Leftrightarrow\)6x = 30
\(\Rightarrow\)x = 5
Vậy x = 5
b) 8x + 2x = 100
\(\Leftrightarrow\)10x = 100
\(\Rightarrow\)x = 10
Vậy x = 10