Question

[~Tiểu Hoa Hoa~]

Tìm x

1)\(\left(x-2\right)^2-\left(x-3\right)\left(x+3\right)=17\)

2)\(\left(2x+3\right)^2-\left(2x-1\right)\left(2x+1\right)=10\)

3)\(x^2+6x-247=0\)

4)\(\left(3x-5\right)\left(2x+3\right)-6x^2=7\)

5)\(\left(x-4\right)^2-\left(x-2\right)\left(x+2\right)=36\)

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Answer 1

[Edogawa Conan]

1) (x - 2)² - (x - 3)(x + 3) = 17

=> x² - 4x + 4 - x² + 9 = 17

=> -4x = 17 - 13

=> -4x = 4

=> x = -1

2) TTT

3) x² + 6x - 147 = 0

=> x² + 19x - 13x - 147 = 0

=> x(x + 19) - 13(x + 19) = 0

=> (x - 13)(x + 19) = 0

=> \(\orbr{\begin{cases}x-13=0\\x+19=0\end{cases}}\)

=> \(\orbr{\begin{cases}x=13\\x=-19\end{cases}}\)

4) (3x - 5)(2x + 3) - 6x² = 7

=> 6x² + 9x - 10x - 15 - 6x² = 7

=> -x - 15 = 7

=> -x = 7 + 15

=> -x = 22

=> x = -22

5) TL