Question

[Nham Nguyen]

Tìm x, y ϵ Z, biết :

                \(\left(x+2\right)^2+4=\dfrac{20}{3\left|y+2\right|+5}\)

Answer 1

[gãi hộ cái đít]

Ta có: \(\left(x+2\right)^2+4\ge4\Rightarrow\dfrac{20}{3\left|y+2\right|+5}\ge4\)

\(\Rightarrow3\left|y+2\right|+5\le5\)

\(\Rightarrow\left|y+2\right|=0\Rightarrow y=-2\)

Vậy x=y=-2