Question

[Ngô Đức Anh]

-Tìm x và y 

  \(\frac{4^x}{2^{x+y}}=8\) và \(\frac{^{9^{x+y}}}{3^{5y}}=243\)

Answer 1

[Despacito]

\(\frac{4^x}{2^{x+y}}=8\)

\(\frac{2^{2x}}{2^x.2^y}=8\)

\(\frac{2^x}{2^y}=8\)

\(2^x=2^3.2^y\)

\(2^x=2^{3+y}\)

\(\Rightarrow x=3+y\)

\(\frac{9^{x+y}}{3^{5y}}=243\)

\(\frac{3^{2x+2y}}{3^{5y}}=3^5\)

\(\frac{3^{2x}.3^{2y}}{3^{5y}}=3^5\)

\(\frac{3^{2x}}{3^{3y}}=3^5\)

\(3^{2x}=3^5.3^{3y}\)

\(3^{2x}=3^{5+3y}\)

\(\Rightarrow2x=3y+5\)

\(\hept{\begin{cases}2x-3y=5\\x=3+y\end{cases}}\Leftrightarrow\hept{\begin{cases}2\left(3+y\right)-3y=5\\x=3+y\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}6+2y-3y=5\\x=3+y\end{cases}}\Leftrightarrow\hept{\begin{cases}-y=-1\\x=3+y\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}y=1\\x=4\end{cases}}\)

vậy...

Answer 2

[Đỗ Xuân Trọng]

\(\frac{4^x}{2^{x+y}}=8\Leftrightarrow2^{2x}=2^{x+y+3}\Leftrightarrow x=y+3\)

\(9^{x+y}=243.3^{5y}\Leftrightarrow3^{2x+2y}=3^{5y+5}\Leftrightarrow2x=3y+5\)

\(\left(x,y\right)=\left(-1;2\right)\)