Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) Ta có: \(\left|2x-1\right|=\left|2x+3\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-1=2x+3\left(loại\right)\\2x-1=-2x-3\end{matrix}\right.\Leftrightarrow2x+2x=-3+1\)
\(\Leftrightarrow4x=-2\)
hay \(x=-\dfrac{1}{2}\)
|2x-3|=5 suy ra:th1:2x-3=5 2x=5+3 2x=8 x=8:2 x=4 th2:2x-3=-5 2x=-5+3 x=-2 x=-2:2 x=-1
1.
a) | 2x+3 |= 5
=>2x+3=\(\pm\) 5
=>\(\left[\begin{array}{nghiempt}2x+3=5\\2x+3=-5\end{array}\right.\) => \(\left[\begin{array}{nghiempt}2x=2\\2x=-8\end{array}\right.\) => \(\left[\begin{array}{nghiempt}x=1\\x=-4\end{array}\right.\)
Vậy x\(\in\)\(\left\{1;-4\right\}\)
a) \(\left|3x-1\right|=5\)
\(\Rightarrow\orbr{\begin{cases}3x-1=5\\3x-1=-5\end{cases}}\Rightarrow\orbr{\begin{cases}3x=6\\3x=-4\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=\frac{-4}{3}\end{cases}}\)
b) \(\left|x-1\right|+11=45\)
\(\Rightarrow\left|x-1\right|=35\)
\(\Rightarrow\orbr{\begin{cases}x-1=35\\x-1=-35\end{cases}\Rightarrow\orbr{\begin{cases}x=36\\x=-34\end{cases}}}\)
c)\(\left|2x+1\right|=\left|2x-3\right|\)
\(\Rightarrow\orbr{\begin{cases}2x+1=2x-3\\2x+1=-2x+3\end{cases}\Rightarrow\orbr{\begin{cases}2x-2x=-3-1\\2x+2x=3-1\end{cases}\Rightarrow}\orbr{\begin{cases}0=-4\\4x=2\end{cases}\Rightarrow}\orbr{\begin{cases}vôlis\\x=\frac{1}{2}\end{cases}}}\)
d)\(\left|x+1\right|-5x=7\)
\(\Rightarrow\left|x+1\right|=7+5x\)
\(\Rightarrow\orbr{\begin{cases}x+1=7+5x\\x+1=-7-5x\end{cases}\Rightarrow\orbr{\begin{cases}x-5x=7-1\\x+5x=-7-1\end{cases}\Rightarrow}\orbr{\begin{cases}-4x=6\\6x=-8\end{cases}\Rightarrow}\orbr{\begin{cases}x=-\frac{3}{2}\\x=-\frac{4}{3}\end{cases}}}\)
hok tốt!!!
2x + 2 = { -[ -x - 3x - 9]}
2x + 2 = x + 3x + 9
2 - 9 = 4x - 2x
2x = -7
x = -7/2
Trả lời:
\(\left|2x+1\right|=\left|2x-3\right|\)
\(\Leftrightarrow\left|2x+1\right|-\left|2x-3\right|=0\)
Vì \(\left|2x+1\right|\ge0\)với \(\forall x\)
\(\left|2x-3\right|\ge0\)với \(\forall x\)
Do đó: \(\left|2x+1\right|-\left|2x-3\right|\ge0\)với \(\forall x\)
Mà\(\left|2x+1\right|-\left|2x-3\right|=0\)
\(\Rightarrow\hept{\begin{cases}2x+1=0\\2x-3=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}2x=-1\\2x=3\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}x=\frac{-1}{2}\\x=\frac{3}{2}\end{cases}}\)
\(\Leftrightarrow x\in\varnothing\)
Vậy \(x\in\varnothing\)
Hok tốt!
Vuong Dong Yet
\(|5x-3|-x=7\)
\(|5x-3|=7+x\)
\(\orbr{\begin{cases}5x-3=7+x\\5x-3=-7-x\end{cases}}\)
\(\orbr{\begin{cases}5x-x=7+3\\5x+x=-7+3\end{cases}}\)
\(\orbr{\begin{cases}4x=10\\6x=-4\end{cases}}\)
\(\orbr{\begin{cases}x=2,5\\x=\frac{-2}{3}\end{cases}}\)
Vậy x = 2,5 hoặc x = -2/3
Hi Hi!
\(\left|2x-3\right|=5\)
\(\Leftrightarrow\orbr{\begin{cases}2x-3=5\\2x-3=-5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}2x=8\\2x=-2\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-1\end{cases}}\)
\(a,\Rightarrow\left[{}\begin{matrix}2x-3=5\\3-2x=5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\\ b,\Rightarrow\left|x-1\right|=1-3x\\ \Rightarrow\left[{}\begin{matrix}x-1=1-3x\\x-1=3x-1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=0\end{matrix}\right.\)
a) \(\Rightarrow\left[{}\begin{matrix}2x-3=5\\2x-3=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=8\\2x=-2\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-1\end{matrix}\right.\)
b) \(\left|x-1\right|+3x=1\left(đk:x\le\dfrac{1}{3}\right)\)
\(\Rightarrow x-1=3x-1\)
\(\Rightarrow2x=0\Rightarrow x=0\left(tm\right)\)
l2x-1l=l2x+3l
=>-(2x - 1) = 2x + 3 hoặc 2x - 1 = 2x + 3
TH1: - (2x - 1) = 2x + 3
-2x + 1 =2x + 3
-2x - 2x = 3 - 1
x . (-2 - 2)=2
-4x =2
x = 2 : (-4)
x =(-1)/2
TH2: 2x - 1 = 2x + 3
2x - 2x= 3 + 1
=>0 = 4
=> x thuộc rỗng
vậy x =(-1)/2