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11 tháng 12 2015

(x-7/2012 +1)+(x-6/2013 +1) =(x-5/2014 +1) +(x-4/2015 +1)

x-2019 /2012 + x-2019 /2013 = x-2019 / 2014 + x-2019 /2015

x-2019 /2012+ x-2019 /2013 - x-2019 /2014 - x-2019 /2015 = 0

(x-2019) * (1/2012 + 1/2013 - 1/2014 -1/2015) = 0

Vì x khác 0 =>1/2012 + 1/2013 -1/2014 -1/2015 khác 0

=> x-2019=0

    x        = 0+2019

    x        = 2019

Vậy x=2019

tick mình nha

7 tháng 9 2021

\(\dfrac{x+5}{2015}+\dfrac{x+6}{2014}+\dfrac{x+7}{2013}+\dfrac{x+8}{2012}=-4\\ \Leftrightarrow\left(\dfrac{x+5}{2015}+1\right)+\left(\dfrac{x+6}{2014}+1\right)+\left(\dfrac{x+7}{2013}+1\right)+\left(\dfrac{x+8}{2012}+1\right)=0\\ \Leftrightarrow\dfrac{x+2020}{2015}+\dfrac{x+2020}{2014}+\dfrac{x+2020}{2013}+\dfrac{x+2020}{2012}=0\\ \Leftrightarrow\left(x+2020\right)\left(\dfrac{1}{2015}+\dfrac{1}{2014}+\dfrac{1}{2013}+\dfrac{1}{2012}\right)=0\\ \Leftrightarrow x+2020=0\\ \Leftrightarrow x=-2020\)

Vậy x = -2020 là nghiệm của pt.

\(\dfrac{x+5}{2015}+\dfrac{x+6}{2014}+\dfrac{x+7}{2013}+\dfrac{x+8}{2012}=-4\)

\(\Leftrightarrow x+2020=0\)

hay x=-2020

8 tháng 7 2017

Giúp mình nhé các bạn mình đang cần gấp lắm

16 tháng 9 2021

\(\dfrac{x-1}{2012}+\dfrac{x-2}{2013}+\dfrac{x-3}{2014}=\dfrac{x-4}{2015}+\dfrac{x-5}{2016}+\dfrac{x-6}{2017}\)

\(\Leftrightarrow\left(\dfrac{x-1}{2012}+1\right)+\left(\dfrac{x-2}{2013}+1\right)+\left(\dfrac{x-3}{2014}+1\right)=\left(\dfrac{x-4}{2015}+1\right)+\left(\dfrac{x-5}{2016}+1\right)+\left(\dfrac{x-6}{2017}+1\right)\)

\(\Leftrightarrow\dfrac{x+2011}{2012}+\dfrac{x+2011}{2013}+\dfrac{x+2011}{2014}-\dfrac{x+2011}{2015}-\dfrac{x+2011}{2016}-\dfrac{x+2011}{2017}=0\)

\(\Leftrightarrow\left(x+2011\right)\left(\dfrac{1}{2012}+\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2015}-\dfrac{1}{2016}-\dfrac{1}{2017}\right)=0\)

\(\Leftrightarrow x=-2011\)( do \(\dfrac{1}{2012}+\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2015}-\dfrac{1}{2016}-\dfrac{1}{2017}\ne0\))

\(\frac{x+5}{2015}+\frac{x+6}{2014}+\frac{x+7}{2013}+\frac{x+8}{2012}+\frac{x+9}{2011}+5=0\)

\(\Rightarrow1+\frac{x+5}{2015}+1+\frac{x+6}{2014}+1+\frac{x+7}{2013}+1+\frac{x+8}{2012}+1+\frac{x+9}{2011}=0\)

\(\Rightarrow\frac{x+2020}{2015}+\frac{x+2020}{2014}+\frac{x+2020}{2013}+\frac{x+2020}{2012}+\frac{x+2020}{2011}=0\)

\(\Rightarrow\left(x+2020\right)\left(\frac{1}{2015}+\frac{1}{2014}+\frac{1}{2013}+\frac{1}{2012}+\frac{1}{2011}\right)=0\)

\(\Rightarrow x+2020=0\)

\(\Rightarrow x=-2020\)

Study well 

2 tháng 9 2019

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