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`x+(x+1)+(x+2)+...+(x+30)=1240`
`=> (x + x + x + ... + x) + (1 + 2 + 3 +... + 30) = 1240`
`=> 31x + 465 = 1240`
`=> 31 x = 1240 - 465`
`⇒ 31x = 775`
`⇒ x = 775 : 31`
`⇒ x = 25`
\(...\Rightarrow x+x+\dfrac{x}{43}+\dfrac{x}{8}=14+148+\dfrac{10}{30}+\dfrac{5}{95}\)
\(\Rightarrow\left(1+1+\dfrac{1}{43}+\dfrac{1}{8}\right)x=162+\dfrac{1}{3}+\dfrac{1}{19}\)
\(\Rightarrow\left(\dfrac{2.43.8}{43.8}+\dfrac{1.8}{43.8}+\dfrac{1.43}{43.8}\right)x=\dfrac{162.3.19}{3.19}+\dfrac{1.19}{3.19}+\dfrac{1.3}{19.3}\)
\(\Rightarrow\left(\dfrac{688}{344}+\dfrac{8}{344}+\dfrac{43}{344}\right)x=\dfrac{9234}{57}+\dfrac{19}{57}+\dfrac{3}{57}\)
\(\Rightarrow\dfrac{739}{344}x=\dfrac{9256}{57}\)
\(\Rightarrow x=\dfrac{9256}{57}:\dfrac{739}{344}=\dfrac{9256}{57}.\dfrac{344}{739}=\dfrac{\text{3184064}}{\text{42123}}\)
Trả lời :
\(x+30\%\cdot x=-\frac{1}{3}\)
\(x+\frac{3}{10}\cdot x=-\frac{1}{3}\)
\(x\left(1+\frac{3}{10}\right)=-\frac{1}{3}\)
\(\frac{13}{10}x=-\frac{1}{3}\)
\(x=-\frac{1}{3}:\frac{13}{10}\)
\(x=-\frac{10}{39}\)
Vậy \(x=-\frac{10}{39}\)
Hok tốt
-Ken-
\(x+30\%x=-1,3\)
\(\Leftrightarrow1x+\frac{30}{100}x=-1,3\)
\(\Leftrightarrow\frac{10}{10}x+\frac{3}{10}x=-1,3\)
\(\Leftrightarrow x\left(\frac{10}{10}+\frac{3}{10}\right)=-1,3\)
\(\Leftrightarrow\frac{13}{10}x=\frac{-13}{10}\)
\(\Leftrightarrow x=\frac{-13}{10}\div\frac{13}{10}\)
\(\Leftrightarrow x=\frac{-13}{10}\times\frac{10}{13}\)
\(\Leftrightarrow x=-1\)
\(x+30\%\cdot x=-1,3\)
\(100\%\cdot x+30\%\cdot x=-1,3\)
\(x\cdot\left(100\%+30\%\right)=-1,3\)
\(x.130\%=-1,3\)
\(x=-1,3:130\%\)
\(x=-1\)
x+30%.x=-1,3
=>x+\(\frac{3}{10}\).x=-1,3
=>x.(\(\frac{3}{10}+1\))=-1,3
=>x.1,3=-1,3
=>x=-1,3:1,3
=>x=-1
x+30%.x=-1,3
x+1/3.x=-1,3
x(1+1/3)=-13/10
x.4/3=-13/10
x= (-13/10) : (4/3)
x=-39/40
Ungr hộ mk nha