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a)
<=> 10x - 35 + 16x - 10 = 5
<=> 10x + 16x = 5 + 35 + 10
<=> 26x = 50
<=> x = 50/26 = 25/13
5x(x - 3)(x + 3) - (2x - 3)2 - 5(x + 2) + 34x(x + 2) = 1
\(\Leftrightarrow-\left(2x-3\right)^2+5x\left(x-3\right)\left(x+3\right)+34x\left(x+2\right)-5\left(x+2\right)-1=0\)
\(\Leftrightarrow\left[-\left(2x-3\right)^2+5x\left(x^2-9\right)-1\right]+\left(x+2\right)\left(34x-5\right)=0\)
\(\Leftrightarrow\left(-4x^2+12x-9+5x^3-45x-1\right)+\left(x+2\right)\left(34x-5\right)=0\)
\(\Leftrightarrow\left(5x^3-4x^2-33x-10\right)+\left(x+2\right)\left(34x-5\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(5x^2-14x-5\right)+\left(x+2\right)\left(34x-5\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(5x^2-14x-5+34x-5\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(5x^2+20x-10\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x^2+4x-2\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-2\\x^2+4x-2=0\left(1\right)\end{array}\right.\)
\(\left(1\right)\Leftrightarrow x^2+4x+4-6=0\)
\(\Leftrightarrow\left(x+2\right)^2=6\)
\(\Leftrightarrow x=\pm\sqrt{6}-2\)
Vậy pt có nghiệm là \(\left[\begin{array}{nghiempt}x=-2\\x=\pm\sqrt{6}-2\end{array}\right.\)
Thực hiện phá ngoặc lần lượt và rút gọn VT = -73x + 36.
Giải phương trình -73x + 36 = 182 thu được x = -2.
a, \(\left(x-2\right)^2-\left(x+3\right)^2-4\left(x+1\right)=5\)
\(\Leftrightarrow x^2-4x+4-\left(x^2+6x+9\right)-4x-4=5\)
\(\Leftrightarrow x^2-4x+4-x^2-6x-9-4x-4=5\)
\(\Leftrightarrow-14x-9=5\)
\(\Leftrightarrow-14x=14\)
\(\Leftrightarrow x=-1\)
Vậy....
b, \(\left(2x-3\right)\left(2x+3\right)-\left(x-1\right)^2-3x\left(x-5\right)=-44\)
\(\Leftrightarrow\left(2x\right)^2-3^2-\left(x^2-2x+1\right)-3x^2+15x=-44\)
\(\Leftrightarrow4x^2-9-x^2+2x-1-3x^2+15x=-44\)
\(\Leftrightarrow-10+17x=-44\)
\(\Leftrightarrow17x=-34\)
\(\Leftrightarrow x=-2\)
Vậy....
c, \(\left(5x+1\right)^2-\left(5x+3\right)\left(5x-3\right)=30\)
\(\Leftrightarrow\left(5x\right)^2+10x+1-\left[\left(5x\right)^2-3^2\right]=30\)
\(\Leftrightarrow\left(5x\right)^2+10x+1-\left(5x\right)^2+9=30\)
\(\Leftrightarrow10x+10=30\)
\(\Leftrightarrow10x=20\)
\(\Leftrightarrow x=2\)
Vậy....
d, \(\left(x+3\right)^2+\left(x-2\right)\left(x+2\right)-2\left(x-2\right)^2=7\)
\(\Leftrightarrow x^2+6x+9+x^2-4-2\left(x^2-4x+4\right)=7\)
\(\Leftrightarrow2x^2+6x+5-2x^2+8x-8=7\)
\(\Leftrightarrow14x-3=7\)
\(\Leftrightarrow14x=10\)
\(\Leftrightarrow x=\frac{10}{14}=\frac{5}{7}\)
Vậy...
\(5x\left(x-3\right)\left(x+3\right)-\left(2x-3\right)^2-5\left(x+2\right)^2\)
\(+34x\left(x+2\right)=1\)
\(\Leftrightarrow5x\left(x^2-9\right)-\left(4x^2-12x+9\right)-5\left(x^2+4x+4\right)\)
\(+34x^2+68x=0\)
\(\Leftrightarrow5x^3-45x-4x^2+12x-9-5x^2-20x-20\)
\(+34x^2+68x=0\)
\(\Leftrightarrow5x^3+25x^2+15x-29=0\)
Giải nghiệm ta được ba nghiệm sau:
\(x_1\approx0,776\)
\(x_2\approx-1,96\)
\(x_3\approx-3,82\)