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Question

Tìm x biết :

x-128=$\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)$

Chúc Nguyễn · Accepted Answer

x - 128 = $\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)$

⇔ x - 128 = $\left(\dfrac{104}{21}-5\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)$

⇔ x - 128 = $\left(\dfrac{-1}{21}\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)$

⇔ x - 128 = -128

⇔ x = -128 + 128

⇔ x = 0

Vậy x = 0Câu trả lời: x - 128 = $\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)$

⇔ x - 128 = $\left(\dfrac{104}{21}-5\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)$

⇔ x - 128 = $\left(\dfrac{-1}{21}\right):\left(\dfrac{-1}{42}\right):\left(\dfrac{-1}{64}\right)$

⇔ x - 128 = -128

⇔ x = -128 + 128

⇔ x = 0

Vậy x = 0

Hải Đăng · Answer

$x-128=\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)$

$\Rightarrow x-128=\left(-\dfrac{1}{21}\right):\left(-\dfrac{1}{42}\right):\left(-\dfrac{1}{64}\right)$

$\Rightarrow x-128=2:\left(-\dfrac{1}{64}\right)$

$\Rightarrow x-128=-128$

$\Rightarrow x=\left(-128\right)+128$

$\Rightarrow x=0$Câu trả lời: $x-128=\left(4\dfrac{20}{21}-5\right):\left(\dfrac{4141}{4242}-1\right):\left(\dfrac{636363}{646464}-1\right)$

$\Rightarrow x-128=\left(-\dfrac{1}{21}\right):\left(-\dfrac{1}{42}\right):\left(-\dfrac{1}{64}\right)$

$\Rightarrow x-128=2:\left(-\dfrac{1}{64}\right)$

$\Rightarrow x-128=-128$

$\Rightarrow x=\left(-128\right)+128$

$\Rightarrow x=0$