Question

[Võ Ngọc Phương Uyên]

Tìm x, biết: \(\frac{1}{2}\cdot2^x+4\cdot2^x-288=0\)

Answer 1

[Trâm Lê]

\(\Rightarrow2^x\left(\frac{1}{2}+4\right)=288\Rightarrow2^x.\frac{9}{2}=288\Rightarrow2^x=64=2^6\Rightarrow x=6\)

Answer 2

[Ming Ming]

\(\)\(\left(\frac{1}{2}+4\right).2^x=288\)

\(\frac{9}{2}.2^x=288\)

\(2^x=64\)

\(2^x=2^6\)

=> x=6