Question

[Nguyễn ngọc Khế Xanh]

tìm x biết :

a) \(\left|x+\dfrac{1}{2}\right|\)=\(\dfrac{5}{2}\)                            b) \(\left|2x-\dfrac{2}{3}\right|\)+\(\dfrac{1}{3}\)=0                c) |x-2| = 2x + 1

Answer 1

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\(\left[{}\begin{matrix}2x-\dfrac{2}{3}=\dfrac{1}{3}\\2x-\dfrac{2}{3}=\dfrac{-1}{3}\end{matrix}\right.\left[{}\begin{matrix}2x=1\\2x=\dfrac{1}{3}\end{matrix}\right.\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=\dfrac{1}{6}\end{matrix}\right.\)

Answer 2

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a)\(\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{5}{2}\\x+\dfrac{1}{2}=-\dfrac{5}{2}\end{matrix}\right.\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)