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\(a)x+30\%x=-1,31\)
\(\Leftrightarrow x+\frac{3x}{10}=-1,31\)
\(\Leftrightarrow10x+3x=-13,1\)
\(\Leftrightarrow13x=-13,1\Leftrightarrow x=-\frac{131}{130}\)
\(b)\left(x-\frac{1}{2}\right):\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
\(\Leftrightarrow\frac{2x-1}{2}.3+\frac{5}{7}=\frac{68}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=\frac{63}{7}\)
\(\Leftrightarrow\frac{6x-3}{2}=9\)
\(\Leftrightarrow6x-3=18\)
\(\Leftrightarrow x=\frac{7}{2}\)
a) 2/3 x = 2/9 + 4/9
=> 2/3 x = 2/3
=> x = 1
b) 4,5 - 2x = 11/14 + \(-1\frac{4}{7}\)
=> 4,5 - 2x = 5/14
=> 2x = 4,5 - 5/14
=> 2x = 29/7
=> x= 29/14
\(\left(2,8x-32\right)\div\frac{2}{3}=-90\)
\(\Rightarrow2,8x-32=-60\)
\(\Rightarrow2,8x=-28\)
\(\Rightarrow x=-10\)
\(\left(4,5-2x\right)\times1\frac{4}{7}=\frac{11}{14}\)
\(\Rightarrow4,5-2x=\frac{1}{2}\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
\(\left(4\frac{1}{2}-\frac{2}{5}x\right):\frac{7}{4}=\frac{11}{14}\)
\(\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{14}.\frac{7}{4}=\frac{11}{8}\)
\(\frac{2}{5}x=\frac{9}{2}-\frac{11}{8}\)
\(\frac{2}{5}x=\frac{25}{8}\)
\(x=\frac{25}{8}.\frac{5}{2}=\frac{125}{16}\)
\(\left(4\frac{1}{2}-\frac{2}{5}x\right):\frac{7}{4}=\frac{11}{14}\)
\(\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{14}x\frac{7}{4}\)
\(\left(\frac{9}{2}-\frac{2}{5}x\right)=\frac{11}{8}\)
\(\frac{2}{5}x=\frac{9}{12}-\frac{11}{8}\)
\(\frac{2}{5}x=\frac{-5}{8}\)
\(x=\frac{-5}{8}:\frac{2}{5}\)
\(x=\frac{-25}{16}\)
a) \(\left|x+3\right|:\left(-15\right)=\frac{1}{3}\)
\(\left|x+3\right|=-5\)
=> không tìm được x
b) \(\left|4,5-2x\right|.\left(-1\frac{4}{7}\right)=-\frac{11}{14}\)
\(\left|4,5-2x\right|=2\)
TH1: 4,5 - 2x = 2
2x = 2,5
x = 1,25
TH2: 4,5 - 2x = -2
2x = 6,5
x = 3,25
KL:...
\(\left(4,5-2.x\right).1\frac{4}{7}=\frac{11}{14}\)
\(\left(4,5-2.x\right).\frac{11}{7}=\frac{11}{14}\)
\(\left(4,5-2.x\right)=\frac{11}{14}:\frac{11}{7}\)
\(4,5-2.x=\frac{1}{2}\)
\(2.x=4,5-\frac{1}{2}\)
\(2.x=4\)
\(x=4:2=2\)
\(\left(4,5-2x\right)\cdot1\frac{4}{7}=\frac{11}{14}\)
\(\left(4,5-2x\right)\cdot\frac{11}{7}=\frac{11}{14}\)
\(4,5-2x=\frac{1}{2}\)
\(\frac{45}{10}-2x=\frac{1}{2}\)
\(2x=4\)
\(x=2\)
\(\left(4,5-2x\right).\frac{14}{7}=\frac{11}{4}\)
\(4,5-2x=\frac{11}{4}:\frac{14}{7}\)
\(4,5-2x=\frac{77}{56}\)
\(2x=\frac{77}{56}+4,5\)
\(2x=\frac{77}{56}+\frac{9}{2}\)
\(2x=\frac{329}{56}\)