Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(\frac{1313}{2828}+x=\frac{2323}{4646}\)
hay \(\frac{13}{28}+x=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{13}{28}\)
\(x=\frac{1}{28}\)
\(\frac{23}{69}-x=\frac{17}{153}\)
hay \(\frac{1}{3}-x=\frac{1}{9}\)
\(x=\frac{1}{3}-\frac{1}{9}\)
\(x=\frac{2}{9}\)
\(a,\frac{1313}{2828}+x=\frac{2323}{4646}\)
\(\frac{13}{28}+x=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{13}{28}=\frac{1}{28}\)
\(b,\frac{5}{7}+\frac{x}{35}=\frac{4}{5}\)
\(\frac{x}{35}=\frac{4}{5}-\frac{5}{7}=\frac{3}{35}\)
\(\Rightarrow x=3\)
\(c,\frac{23}{69}-x=\frac{17}{153}\)
\(\frac{1}{3}-x=\frac{1}{9}\)
\(x=\frac{1}{3}-\frac{1}{9}=\frac{2}{9}\)
\(a,\frac{1313}{2828}+x=\frac{2323}{4646}\)
\(\frac{13}{28}+x=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{13}{28}=\frac{1}{28}\)
\(b,\frac{5}{7}+\frac{x}{35}=\frac{4}{5}\)
\(\frac{x}{35}=\frac{4}{5}-\frac{5}{7}=\frac{3}{35}\)
\(\Rightarrow x=3\)
\(c,\frac{23}{69}-x=\frac{17}{153}\)
\(x=\frac{23}{69}-\frac{17}{153}=\frac{2}{9}\)
a)\(\Leftrightarrow\)\(x=\dfrac{2323}{4646}-\dfrac{1313}{2828}\)
\(\Leftrightarrow\)\(x=\dfrac{1}{28}\)
b)\(\Leftrightarrow\)\(x=\dfrac{23}{69}-\dfrac{17}{153}\)
\(\Leftrightarrow\)\(x=\dfrac{2}{9}\)
a) \(\dfrac{1313}{2828}\) + \(x\) = \(\dfrac{2323}{4646}\)
\(\dfrac{13}{28}\) + \(x\) = \(\dfrac{1}{2}\)
\(x=\dfrac{1}{2}-\dfrac{13}{28}\)
\(x=\dfrac{14}{28}-\dfrac{13}{28}\)
\(x=\dfrac{1}{28}\)
a: =>x+7/4=6:2/3=9
=>x=29/4
b: =>x:5/3=7/5
=>x=7/5*5/3=7/3
c:=>x+1/6=5/3
=>x=10/6-1/6=3/2
d: =>x+4/5=4/5+3/7+3/5
=>x=3/7+3/5=36/35
e: =>x/35=4/5-5/7=3/35
=>x=3
f: =>13/28+x=1/2
=>x=1/28
g: =>1/3-x=1/9
=>x=2/9
Bài làm
\(\frac{1313}{1010}+x=\frac{1414}{2828}\)
\(\Rightarrow\frac{13}{10}+x=\frac{14}{28}\)
\(x=\frac{14}{28}-\frac{13}{10}\)
\(x=\frac{1}{2}-\frac{13}{10}\)
\(x=\frac{10}{20}-\frac{26}{20}\)
\(x=-\frac{16}{20}\)
\(x=-\frac{4}{5}\)
Vậy \(x=-\frac{4}{5}\)
1313/2828 - x = 2323/4646
13/28 - x = 1/2
x = 13/28 - 1/2
x = -1/28 < 0 (lớp 4 chưa học số âm, em xem lại đề nhé)
\(\dfrac{1313}{2828}-x=\dfrac{2323}{4646}\)
\(\dfrac{13\times101}{28\times101}-x=\dfrac{1}{2}\)
\(\dfrac{13}{28}-x=\dfrac{1}{2}\)
\(x=\dfrac{13}{28}-\dfrac{1}{2}\)
\(x=-\dfrac{1}{28}\)