Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) ( 509 + 355 ) : x = 840 : 35
864 : x = 24
x = 864 : 24
x = 36
b) 890 : x = 35 dư 15
=> 890 : x - 15 = 35
=> 890 : x = 35 + 15
=> 890 : x = 50
=> x = 17,8
A) ( 509 + 355 ): x = 840 : 35
= 864 : x = 24
x = 864 : 24
x = 36
B) 890 : x = 35 dư 15
x = 890 : 35
x = 25,428
a) 156 - ( x + 61 ) = 82
<=> x + 61 = 74
<=> x = 13
b ) x : ( 111 - 99 ) = 17 , 5
<=> x : 12 = 17 , 5
,=> x = 210
c) ( 509 + 355 ) : x = 840 : 35
<=> 864 : x = 24
,=> x = 36
a) 156 - ( x + 16 ) = 82 x : ( 111 - 99 ) = 17.5
x + 16 = 156 - 82 x : 12 = 17.5
x + 16 = 74 x = 17.5 x 12
x = 74 - 16 x = 210
x = 58 Vậy x = 210
Vậy x = 58
c) ( 509 + 355 ) : x = 840 : 35
864 : x = 840 : 35
864 : x = 24
x = 864 : 24
x = 36
Vậy x = 36
vi 890 : x = 35 du 15
nen 890 : x = 35 +15 hay 890 : x = 50
vay x = 890 : 50
x = 17.8
Ta có: 890:x=35 [dư 15]
[890-15] :x=35
875 : x = 35
x = 875:35
x = 25
Cho mình
a,(x-15).35=0(dấu chấm là nhân nhá)
x-15=0:35=0
x=0+15
x=15
câu 1
( 35+x) - 81 = 54
( 35+x) = 54+81
35+x = 135
x = 135 - 35
x = 100
1/
a)28+2x=35-(-13)
28+2x=48
2x=48-28
x=20:2
x=10
b)2(x+1)2=-7+15
2(x+1)2=8
(x+1)2=4
x+12=22
x+1=2
x=1
c)(-25)-(x+5)=415+5(x-83)
-25-5-x=415+5x-415
-30-x=5x
-30=x+5x=6x
x=-30:6
x=-5
d)|x-2|+(-7)=-3
|x-2|=-3+7
|x-2|=4
=>x-2=4 hoặc x-2=-4
=>x=6 hoặc x=-2
Vậy x=6 hoặc x=-2
Bài 1:
a) Ta có: \(\dfrac{2}{5}\cdot x+\dfrac{1}{3}=\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{2}{5}\cdot x=\dfrac{1}{5}-\dfrac{1}{3}=\dfrac{-2}{15}\)
\(\Leftrightarrow x=\dfrac{-2}{15}:\dfrac{2}{5}=\dfrac{-2}{15}\cdot\dfrac{5}{2}\)
hay \(x=-\dfrac{1}{3}\)
Vậy: \(x=-\dfrac{1}{3}\)
b) Ta có: \(\dfrac{1}{5}+\dfrac{5}{3}:x=\dfrac{1}{2}\)
\(\Leftrightarrow\dfrac{5}{3}:x=\dfrac{1}{2}-\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{3}{10}=\dfrac{5}{3}\cdot\dfrac{10}{3}\)
hay \(x=\dfrac{50}{9}\)
Vậy: \(x=\dfrac{50}{9}\)
c) Ta có: \(\dfrac{4}{9}-\dfrac{5}{3}\cdot x=-2\)
\(\Leftrightarrow\dfrac{5}{3}x=\dfrac{4}{9}+2=\dfrac{22}{9}\)
\(\Leftrightarrow x=\dfrac{22}{9}:\dfrac{5}{3}=\dfrac{22}{9}\cdot\dfrac{3}{5}\)
hay \(x=\dfrac{22}{15}\)
Vậy: \(x=\dfrac{22}{15}\)
d) Ta có: \(\dfrac{5}{7}:x-3=\dfrac{-2}{7}\)
\(\Leftrightarrow\dfrac{5}{7}:x=\dfrac{-2}{7}+3=\dfrac{19}{21}\)
\(\Leftrightarrow x=\dfrac{5}{7}:\dfrac{19}{21}=\dfrac{5}{7}\cdot\dfrac{21}{19}\)
hay \(x=\dfrac{15}{19}\)
Vậy:\(x=\dfrac{15}{19}\)
\(a,x:\left(111-99\right)=17\cdot5\\ \Leftrightarrow x:12=85\\ \Leftrightarrow x=1020\\ b,\left(509+335\right):x=840:35\\ \Leftrightarrow844:x=24\\ \Leftrightarrow x=\dfrac{211}{6}\\ c,\left(x+1\right)+\left(x+2\right)+...+\left(x+28\right)=462\\ \Leftrightarrow28x+406=462\\ \Leftrightarrow28x=56\\ \Leftrightarrow x=2\)
d, 890 : x = 35 dư 15
\(\Rightarrow35x+15=890\\ \Leftrightarrow35x=875\\ \Leftrightarrow x=25\)