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\(a,x:\left(111-99\right)=17\cdot5\\ \Leftrightarrow x:12=85\\ \Leftrightarrow x=1020\\ b,\left(509+335\right):x=840:35\\ \Leftrightarrow844:x=24\\ \Leftrightarrow x=\dfrac{211}{6}\\ c,\left(x+1\right)+\left(x+2\right)+...+\left(x+28\right)=462\\ \Leftrightarrow28x+406=462\\ \Leftrightarrow28x=56\\ \Leftrightarrow x=2\)
d, 890 : x = 35 dư 15
\(\Rightarrow35x+15=890\\ \Leftrightarrow35x=875\\ \Leftrightarrow x=25\)
a) (3x-12) :8 +10= 13
<=> (3x-12):8 = 13-10 = 3
<=> 3x-12 = 3 .8 = 24
<=> 3x = 24+12=36
<=> x=36:3=12
b) (x+5).8-20 = 60
<=> (x+5) .8 = 60+20=80
<=> x+5 = 80:8 = 10
<=> x=10-5 = 5
c) 3.[35+(x-10)]-375 = 0
<=> 3.[35+(x-10)] = 0 +375=375
<=> 35+(x-10) = 375 :3 = 125
<=> x-10 = 125-35=90
<=> x = 90+10 = 100
d) ( 158x+173-24) :35 = 81
<=> 158x+149 = 81 . 35 = 2835
<=> 158x = 2835 -149= 2686
<=> x= 2686 : 158 = 17
e) x - 140 : 35 = 0
<=> x-4 = 0
<=> x=0+4 = 4
(3x - 12 ) : 8 + 10 = 13
(3x - 12 ) : 8 = 13 - 10 = 3
(3x - 12 ) = 3 x 8 = 24
3x = 24 - 12 = 12
x =13 : 3 = 4
( x + 5 )
890 : x = 35 (dư 15)
=> 890 - 15 = 35 . x
=> 35 . x = 875
=> x = 875 : 35
=> x = 25
Vậy x = 25
Ủng hộ mk nha ^_-
vi 890 : x = 35 du 15
nen 890 : x = 35 +15 hay 890 : x = 50
vay x = 890 : 50
x = 17.8
Ta có: 890:x=35 [dư 15]
[890-15] :x=35
875 : x = 35
x = 875:35
x = 25
Cho mình
890:x=35 dư 15
=> 890=35x+15
890-15=35x
875=35x
875:35=x
x=25
890:x=35 dư 5=>890-5=35 x X
=>35 x X=885
=> X =\(\frac{177}{7}\)
a/ (3x -12 ):8+10=13
<=>(3x-12):8=3
<=>3x-12=24
<=>3x=36
<=>x=12
b/(x+5)x8-20=60
<=>(x+5)x8=80
<=>x+5=80:8
<=>x+5=10
x=5
c/3x[35+(x-10)]-375=0
<=>3x[35+(x-10)]=375
<=>35+(x+10)=125
<=>x+10=90
x=80
d/(158x+173-24):35=81
<=>158x+173-24=2835
<=>158x+173=2859
<=>158x=2686
<=>x=17
e/x-140:35=0
<=>x-140=0
<=>x=140+0
x=140
câu 1
( 35+x) - 81 = 54
( 35+x) = 54+81
35+x = 135
x = 135 - 35
x = 100