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X x ( 96 + 0,5 ) = 2017
X x 96,5 = 2017
X = 2017 : 96,5
X = 20,9
Vậy X = 20,9
Tìm x,biết:
a)x*96+x:0,25=48,32
b)x:0,25+x+x*95=73,74
c)x:0,5+x:0,25+x+x*93=35,36
d)x:0,125+x+x*91=78,56
a: =>100x=48,32
hay x=0,4832
b: =>4x+x+95x=73,74
=>100x=73,74
hay x=0,7374
c: =>2x+4x+x+93x=35,36
=>100x=35,36
hay x=0,3536
a)Xx96+x:0,25=48,32
Xx96+Xx4 =48,32
X x(96+4) =48,32
Xx 100 =48,32
X =48,32:100
X = 0,4832
b)x:0,25+x+Xx95 =73,74
Xx4 +Xx1+Xx95= 73,74
X x(4+1+95) =73,74
X x 100 =73,74
X =73,74:100
X = 0,7374
c)x:0,5+x:0,25+x+Xx93=35,36
Xx2 + Xx4+Xx1+Xx93=35,36
Xx(2+4+1+93) = 35,36
Xx 100 = 35,36
X =35,36:100
X =0,3536
d)X:0,125+X+Xx91=78,56
Xx 8+Xx1+Xx91=78,56
Xx(8+1+91) =78,56
Xx 100 =78,56
X =78,56:100
X =0,7856
20x +(1+6+11+.....+96)=990
20x + 970=990
20x=990-997
20x=20
x=1
(x+1)+(x+6)+...+(x+96)=990
\(\Leftrightarrow\)20x+(1+6+11+...+96) = 990
\(\Leftrightarrow\)20x + \(\frac{\left(1+96\right)\times\left[\left(96-1\right):5+1\right]}{2}\)= 990
\(\Leftrightarrow\)20x+970=990
\(\Leftrightarrow\)20x=990-970=20
\(\Leftrightarrow\)x=1
Vậy x= 1
`a)x xx96+x xx0,25=22,23`
`x xx96+x xx4=22,23`
`x xx(96+4)=22,23`
`x xx10=22,23`
`x=22,23:10=2,223`
`b)x:0,25+x xx95+x=10,23`
`x xx4+x xx95+x=10,23`
`x xx(4+95+1)=10,23`
`x xx10=10,23`
`x=10,23:10=1,023`
a: =>96x+4x=22,23
=>100x=22,23
hay x=0,2223
b: =>4x+95x+x=10,23
=>100x=10,23
hay x=0,1023
( x + 1 ) + ( x + 6 ) + ( x + 11 ) + ... + ( x + 96 ) = 990
=> ( x + x + x + ... + x ) + ( 1 + 6 + 11 + ... + 96 ) = 990
20 số x
=> x . 20 + 970 = 990
=> x . 20 = 990 - 970
=> x . 20 = 20
=> x = 20 : 20
=> x = 1
Chúc bạn học tốt nha !!!
`[ ( 2 xx x - 11 ) : 3 + 1 ] xx 5 = 20`
`( 2 xx x - 11 ) : 3 + 1=20:5`
`( 2 xx x - 11 ) : 3 + 1=4`
`( 2 xx x - 11 ) : 3 =4-1`
`( 2 xx x - 11 ) : 3 =3`
`2xx x -11=3xx3`
`2xx x -11=9`
`2xx x =9+11`
`2 xx x=20`
`x=20:2`
`x=10`
Vậy `x=10`
`b, x - 96 = ( 443 - x ) - 15`
`x-96=443-x-15`
` x+x=443-15+96`
`2x=524`
`x=524:2`
`x= 262`
Vậy `x=262`
\(#Nqoc\)
`a)`
\([ ( 2 \times x - 11 ) \div 3 + 1 ] \times 5 = 20\)
`(2 \times x - 11) \div 3 + 1 = 20 \div 5`
`(2 \times x - 11) \div 3 + 1 = 4`
`(2 \times x - 11) \div 3 = 4 - 1`
`(2 \times x - 11) \div 3 = 3`
`2 \times x - 11 = 3 \times 3`
`2 \times x - 11 = 9`
`2 \times x = 9 + 11`
`2 \times x = 20`
`x = 20 \div 2`
`x = 10`
Vậy, `x = 10`
`b)`
\(x - 96 = ( 443 - x ) - 15\)
`x - 96 = 443 - x - 15`
`x - 96 = 428 - x`
`x = 428 - x + 96`
`x = 524 - x`
`x - 524 + x = 0`
`(x + x) - 524 = 0`
`2x - 524 = 0`
`2x = 524`
`x = 524 \div 2`
`x = 262`
Vậy, `x = 262.`
Dãy số 1; 6; 11; ...; 96 có: ( 96 -1 ) : 5 + 1 = 20 số
(x + 1 ) + (x + 6 ) +(x + 11) +...+ ( x +96) =1010
(x + x + x +...+ x ) + ( 1 + 6 + 11+...+ 96 ) = 1010
\(20\times x+\left(96+1\right).20:2=1010\)
\(20\times x+970=1010\)
\(20\times x=1010-970\)
\(20\times x=40\)
\(x=2\)
Ta có : (x+1)+(x+6)+(x+11)+...+(x+96) =1010
=>x+1+x+6+x+11+...+x+96=1010
=>(x+x+x+...+x)+(1+6+11+...+96)=1010
=>20×x+(1+96)×20÷5=1010
=>20×x+388=1010
=>20×x=622
=>x=622÷20
=>x=31,1
\(a.\left(x\times0,25+1999\right)\times2000=2052\times2000\\ \left(x\times0,25+1999\right)\times2000=4104000\\ x\times0,25+1999=4104000:2000\\ x\times0,25+1999=2052\\ x\times0,25=2052-1999\\ x\times0,25=53\\ x=53:0,25\\ x=212\)
( x * 0,25 + 1999 ) * 2000 = ( 53 + 1999 ) * 2000
=> x * 0,25 = 53
=> x = 53 : 0,25
=> x = 212
( 53 + 1999 ) * 2000 = 4104000
x = (4104000 : 2000 - 1999 ) : 0,25
x = 53 : 0,25
x = 212
=>100x=2000
hay x=20
X x (96+4)=2000
X x 100=2000
X = 2000:100
X = 20