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\(8x+7x-2x+x=28\Leftrightarrow14x=28\Leftrightarrow x=2\)
a/ \(2x^3=8x\)
\(2.8=2x^3\)
\(16=2x^3\)
\(x^3=16:2\)
\(x^3=8\)
\(x=2\)
phần b mk chưa nghiên cứu dc
\(58x-20x+x=78\)
\(\Leftrightarrow39x=78\)
\(\Leftrightarrow x=2\)
\(\Leftrightarrow2x+3⋮2x-1\)
\(\Leftrightarrow2x-1\inƯ\left(4\right)\)
\(\Leftrightarrow2x-1\in\left\{-1;1\right\}\)
hay \(x\in\left\{0;1\right\}\)
\(6\cdot x+9=15\)
\(\Rightarrow6\cdot x=15-9\)
\(\Rightarrow6\cdot x=6\)
\(\Rightarrow x=\dfrac{6}{6}=1\)
_______________
\(43+2x=49\)
\(\Rightarrow2x=49-43\)
\(\Rightarrow2x=6\)
\(\Rightarrow x=\dfrac{6}{2}=3\)
____________
\(x:2+5=11\)
\(\Rightarrow x:2=11-5\)
\(\Rightarrow x:2=6\)
\(\Rightarrow x=6\cdot2=12\)
______________
\(77-11x=0\)
\(\Rightarrow11x=77\)
\(\Rightarrow x=\dfrac{77}{11}\)
\(\Rightarrow x=7\)
_______________
\(12-4:x=8\)
\(\Rightarrow4:x=12-8\)
\(\Rightarrow4:x=4\)
\(\Rightarrow x=\dfrac{4}{4}=1\)
_____________
\(x:3+8=11\)
\(\Rightarrow x:3=11-8\)
\(\Rightarrow x:3=3\)
\(\Rightarrow x=3\cdot3=9\)
a: 6x+9=15
=>6x=6
=>x=1
b: 2x+43=49
=>2x=6
=>x=3
c: x:2+5=11
=>x:2=6
=>x=12
d: 77-11x=0
=>7-x=0
=>x=7
e: 12-4:x=8
=>4:x=4
=>x=1
f: x:3+8=11
=>x:3=3
=>x=9
\(\Leftrightarrow14-\frac{72}{-\left(8+x\right)}=-23\)
\(\Leftrightarrow37+\frac{72}{8+x}=0\)
\(\Leftrightarrow37\left(8+x\right)+72=0\)
\(\Leftrightarrow296+37x+72=0\)
\(\Leftrightarrow37x=-368\Leftrightarrow x=-\frac{368}{37}\)
|2x-10|+2x-10=0
=> |2x-10| = 0 - (2x+10)
=> |2x-10| = - (2x+10)
=> 2x-10 < = 0
=> 2x < = 10
=> x < = 10 : 2
=> x < = 5
Vậy x < = 5
Tk mk nha
\(\left|2x-10\right|+2x-10=0\)
\(\Leftrightarrow\left|2x-10\right|=-\left(2x-10\right)\)
\(\Leftrightarrow2x-10\le0\)
\(\Leftrightarrow2x\le10\)
\(\Leftrightarrow x\le5\)
`8x+2x=25 . 2^2`
`=>(8+2)x=25 . 4`
`=>10x=100`
`=>x=100:10`
`=>x=10`