Question

[ღ๖ۣۜT๖ۣۜG๖ۣۜQ_ Đức_ Bênh๖ۣۜ ᶦᵈᵒᶫ๖ۣۜ...]

Tìm x :( -5 ) + | 3x - 1 | + 6 = | -4 |

Answer 1

[나 재민]

\(\left(-5\right)+\left|3x-1\right|+6=\left|-4\right|\)

\(\Rightarrow\left(-5\right)+\left|3x-1\right|+6=4\)

\(\Rightarrow\left|3x-1\right|=4-6+5\)

\(\Rightarrow\left|3x-1\right|=3\)

\(\Rightarrow\orbr{\begin{cases}3x-1=3\\3x-1=-3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-2}{3}\end{cases}}\)

_Học tốt_

Answer 2

[•Mυη•]

\(\left(-5\right)+\left|3x-1\right|+6=\left|-4\right|\)

\(\Leftrightarrow\left(-5\right)+\left|3x-1\right|+6=4\)

\(\Leftrightarrow\left(-5\right)+\left|3x-1\right|=-2\)

\(\Leftrightarrow\left|3x-1\right|=3\)

\(\Leftrightarrow\orbr{\begin{cases}3x-1=3\\3x-1=-3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{-2}{3}\end{cases}}\)

Vậy \(x\in\left\{\frac{4}{3};\frac{-2}{3}\right\}\)