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![](https://rs.olm.vn/images/avt/0.png?1311)
a)225=32.52
270=2.5.33
360=23.32.5
=> ƯCLN 225;270;360=32.5=45
=>ƯC225;270;360=ước 45=1;3;5;9;15;45
b)540=22.33.5
756=33.22.7
1512=33.23.7
=>ưcln 540;756;1512=22.33=108
=>ưc 540;756;1512=ư 108=1;2;3;4;6;9;12;18;24;27;36;48;54;72;108
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có : 225 = 32. 52
270 = 2 . 33 . 5
360 = 23. 32.5
→ ƯCLN= 32. 5 = 45
→ ƯC( 225,270,360)= Ư(45)
→ Ư(45) = \(\left\{1;3;5;9;15;45\right\}\)
Vậy ƯC( 225 ; 270; 360) =\(\left\{1;3;5;9;15;45\right\}\)
b) Ta có : 540 = 22. 33.5
756 = 22.33.7
1512 = 23. 33.7
→ ƯCLN( 540;756;1512)=22.33=108
→ƯC(540;756;1512)=Ư( 108)= \(\left\{1;2;3;4;6;9;12;18;27;36;54;108\right\}\)
Vậy ƯC( 540; 756;1512)= \(\left\{1;2;3;4;6;9;12;18;27;36;54;108\right\}\)
a, Ta có : 225 = \(3^2.5^2\)
270 = \(2.3^3.5\)
360 = \(2^3.3^2.5\)
ƯCLN\(_{\left(225,270,360\right)}\)= \(3^2.5=45\)
\(ƯC_{\left(225,270,360\right)}=Ư_{\left(45\right)}=\left\{1;3;5;9;15;45\right\}\)b, Ta có : 540 = \(2^2.3^3.5\)
756 = \(2^2.3^3.7\)
1512 = \(2^3.3^3.7\)
\(\RightarrowƯCLN_{\left(540,756,1512\right)}=2^2.3^3=108\)
\(ƯC_{\left(540,756,1512\right)}=Ư_{\left(108\right)}=\left\{1;2;3;4;6;9;12;18;108\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có : 506 = 2 . 11 . 23
759 = 3 . 11 . 13
1711 = 29 . 59
=> UNCL( 506 , 729 , 1711 ) = 1
=> Tập hợp các ƯC của 506 , 759 , 1711 = { 1 }
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,ƯCLN\left(540,168\right)=12\\ \RightarrowƯC\left(540,168\right)=Ư\left(12\right)=\left\{-12;-6;-4;-3;-2;-1;1;2;3;4;6;12\right\}\\ b,ƯCLN\left(735,350\right)=35\\ \RightarrowƯC\left(735,350\right)=Ư\left(35\right)=\left\{-35;-7;-5;-1;1;5;7;35\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài này dễ mà
a ) 48 và 72
48 = 24.3
72 = 23.32
ƯCLN ( 48,72 ) = 23.3 = 12
b ) 132 và 156
132 = 22.3.11
156 = 22.3.13
ƯCLN = 22.3 = 12
a, 48 = 2\(^4\) . 3
72 = 2\(^3\) . 3\(^2\)
ƯCLN(48;72) = 2\(^3\).3= 24
ƯC(48;72)=Ư(24)\(\in\)\(\left\{1;2;3;4;6;8;12;24\right\}\)
=> ƯC(48;72)\(\in\)\(\left\{1;2;3;4;6;8;12;24\right\}\)
b,132=2\(^2\).3.11
156=2\(^2\).3.13
ƯCLN(132;156)=2\(^2\).3=12
ƯC(132;156)=Ư(12)\(\in\)\(\left\{1;2;3;4;6;12\right\}\)
=>ƯC132;156)\(\in\)\(\left\{1;2;3;4;6;12\right\}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: BCNN(105;120)=840
BC(105;120)={840;1680;...}
b: BCNN(192;440)=10560
BC(192;440)={10560;21120;...}
c: BCNN(252;792)=5544
d: BCNN(45;120;270)=1080
e: BCNN(128;192;320)=1920
f: BCNN(135;225;405)=2025
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 72 và 60. ===> Lưu ý: VD: 2^2 = 2 mũ 2
72 = 3^2.2^3
60 = 5.3.2^2
ƯCLN (72,60) = 3.2^2 = 12
ƯC = Ư(12) = {1,2,3,4,6,12}
b) 90; 180 và 315
90 = 5.3^2.2
180 = 5.3^2.2^2
315 = 5.3^2.7
ƯCLN (90,180,315) = 5.3^2 = 125
ƯC = Ư(125) = { 1,125 }
![](https://rs.olm.vn/images/avt/0.png?1311)
a: UCLN(24;40)=8
UC(24;40)={1;2;4;8}
b: UCLN(42;98)=14
UC(42;98)={1;2;7;14}
a: UCLN(48;72)=24
UC(48;72)={1;2;3;4;6;8;12;24}
b: UCLN(132;156)=12
UC(132;156)={1;2;3;4;6;12}
c: UCLN(225;270;360)=45
UC(225;270;360)={1;3;5;9;15;45}
d: UCLN(540;756;1512)=108
UC(540;756;1512)={1;2;3;4;6;9;12;18;27;36;54;108}