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Câu hỏi của nguyễn ngọc khánh vân - Toán lớp 7 - Học toán với OnlineMath
Em tham khảo nhé!
\(\frac{2}{7}\)A = \(\frac{3}{10}\)B x \(\frac{4}{9}\)= \(\frac{2}{15}\)B => \(\frac{A}{B}\)= \(\frac{2}{15}\)\(=\frac{7}{15}\)
\(\frac{2}{7}\)
ta có 2/7 của A = 4/9 . 3/10 .B
=> 2/7 . A = 2/15 . B
=> A = 2/15 . B : 2/7
=> A = 7/15 . B
vậy A= 7/15 của B
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Ta có :
\(\frac{2}{7}A=\frac{4}{9}\left(\frac{3}{10}B\right)\)
\(\frac{2}{7}A=\frac{2}{15}B\)
\(\frac{A}{B}=\frac{\frac{2}{15}}{\frac{2}{7}}=\frac{7}{15}\)
Vậy ...