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a)
\(\Rightarrow3^{-2}.\left(3^3\right)^n=3^n\)
\(\Rightarrow3^{-2}.3^{3n}=3^n\)
\(\Rightarrow3^{3n-2}=3^n\)
\(\Rightarrow3n-2=n\)
\(\Rightarrow n=1\)
b)
\(\Rightarrow3^{4+n-2}=3^7\)
\(\Rightarrow x^{n+2}=3^7\)
\(\Rightarrow n+2=7\)
\(\Rightarrow n=5\)
c)
\(\Rightarrow2^n\left(\frac{1}{2}+4\right)=9.2^5\)
\(\Rightarrow2^n.4,5=9.2^5\)
\(\Rightarrow2^n=2.2^5\)
\(\Rightarrow2^n=2^6\)
\(\Rightarrow n=6\)
d)
\(\Rightarrow\left(2^5\right)^{-n}.\left(2^4\right)^n=2048\)
\(\Rightarrow2^{n-5n}=2^{11}\)
\(\Rightarrow-4n=11\)
\(\Rightarrow n=-\frac{4}{11}\)
\(\frac{1}{9}.27^n=3^n\)
\(\Rightarrow\frac{3^n}{27^n}=\frac{1}{9}\)
\(\Rightarrow\left(\frac{3}{27}\right)^n=\frac{1}{9}\)
\(\Rightarrow\left(\frac{1}{9}\right)^n=\frac{1}{9}\)
\(\Rightarrow n=1\)
a) \(\frac{1}{9}.27^n=3^n\)
\(\Leftrightarrow3^{-2}.3^{3n}=3^n\)
\(\Leftrightarrow3^{3n-2}=3^n\)
\(\Leftrightarrow3n-2=n\)
\(\Leftrightarrow2n=2\)
\(\Leftrightarrow n=1\)
b)\(3^{-2}.3^4.3^n=3^7\)
\(\Leftrightarrow3^{2+n}=3^7\)
\(\Leftrightarrow2+n=7\)
\(\Leftrightarrow n=5\)
a)\(32^{-n}\cdot16^n=2048\)
\(\left(2^5\right)^{-n}\cdot\left(2^4\right)^n\)=2048
\(2^{-5n}\cdot2^{4n}\)=\(2^{11}\)
\(2^{-5n+4n}=2^{11}\)
\(2^{-x}=2^{11}\)
\(\Rightarrow x=-11\)
b)\(2^{-1}\cdot2^n+4\cdot2^n=9\cdot2^5\)
\(\frac{1}{2}\cdot2^n+4\cdot2^n=288\)
\(2^n\left(\frac{1}{2}+4\right)=288\)
\(2^n\cdot\frac{9}{2}=288\)
\(2^n=288:\frac{9}{2}\)
\(2^n=64\)
\(2^n=2^6\)
\(\Rightarrow n=6\)
a) 32-n . 16n = 2048
\(\frac{1}{32n}\) . 16n = 2048
\(\frac{1}{2^n.16^n}\) . 16n = 2048
\(\frac{1}{2^n}\) = 2048
2-n = 2048
2-n = 211
\(\Rightarrow\) -n = 11
\(\Rightarrow\) n = -11
Vậy n = -11
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