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A = 2.22 + 3.23 + 4.24 + ... + n.2n
2.A = 2.23 + 3.24 + 4.25 + ...+ n.2n+1
=> A - 2.A = 2.22 + (3.23 - 2.23) + (4.24 - 3.24) + ...+ (n - n + 1).2n - n.2n+1
=> A = 2.22 + 23 + 24 + ..+ 2n - n.2n+ 1 = 22 + (22 + 23 + ....+ 2n+ 1) - (n+1).2n+1
=> A = - 22 - (22 + 23 + ....+ 2n+ 1) + (n+1).2n+1
Tính B = 22 + 23 + ....+ 2n+ 1 => 2.B = 23 + ....+ 2n+ 1 + 2n+2 => 2B - B = 2n+2 - 22 => B = 2n+2 - 22
Vậy A = 22 - 2n+2 + 22 + (n+1).2n+1 = (n+1).2n+1 - 2n+ 2 = 2n+1.(n + 1 - 2) = (n-1).2n+1 = 2(n-1).2n
Theo bài cho A = 2(n-1).2n = 2n+10 => 2(n - 1) = 210 => n - 1 = 29 = 512 => n = 513
Vậy.............
Đặt \(A=2.2^2+3.2^3+4.2^4+5.2^5+...+n.2^n\)
\(\Rightarrow2A=2.2^3+3.2^4+4.2^5+5.2^6+...+n.2^{n+1}\)
\(\Rightarrow2A-A=2.2^3+3.2^4+4.2^5+5.2^6+...+n.2^{n+1}\)
\(-2.2^2-3.2^3-4.2^4-5.2^5-...-n.2^n\)
\(A=n.2^{n+1}-2^3-\left(2^3+2^4+...+2^n\right)\)
Đặt \(M=\left(2^3+2^4+...+2^n\right)\)
\(\Rightarrow2M=\left(2^4+2^5+...+2^{n+1}\right)\)
\(\Rightarrow M=2^{n+1}-2^3\)
\(\Rightarrow A=n.2^{n+1}-2^3-2^{n+1}+2^3\)
\(\Rightarrow A=\left(n-1\right)2^{n+1}=2^{n+10}\)
\(\Rightarrow\left(n-1\right)=2^9\)
\(\Rightarrow n=513\)
Đặt \(A=2.2^2+3.2^3+4.2^4+...+n.2^n=2^{n+10}\)
\(\Rightarrow2A=2.2^3+3.2^4+4.2^5+...+n.2^{n+1}\)
\(\Rightarrow2A-A=2.2^3+3.2^4+4.2^5+...+n.2^{n+1}-2.2^2-3.2^3-4.2^4-...-n.2^n\)
\(\Leftrightarrow A=-2.2^2+\left(2.2^3-3.2^3\right)+\left(3.2^4-4.2^4\right)+...+[\left(n-1\right)2^n-n.2^n]+n.2^{n+1}\)
\(\Leftrightarrow A=-2.2^2-2^3-2^4-...-2^n+n.2^{n+1}\)
\(\Leftrightarrow A=-2^3-\left(2^4-2^3\right)-\left(2^5-2^4\right)-...-\left(2^{n+1}-2^n\right)+n.2^{n+1}\)
\(\Leftrightarrow A=-2^3-2^4+2^3-2^5+2^4-...-2^{n+1}+2^n+n.2^{n+1}\)
\(\Leftrightarrow A=-2^{n+1}+n.2^{n+1}\)
\(\Leftrightarrow A=2^{n+1}\left(n-1\right)\)
Mà \(A=2^{n+10}=2^{n+1}.2^9=2^{n+1}.512\)
\(\Rightarrow n-1=512\)
\(\Rightarrow n=513\)
Đặt A = 2.22 + 3.23 + 4.24 + ... + n.2n
2A = 2.23 + 3.24 + 4.25 + ... + n.2n+1
2A - A = (2.23 - 3.23) + (3.24 - 4.24) + ... + [(n-1).2n - n.2n] + n.2n+1
A = -23 - 24 - ... - 2n + n.2n+1 - 2.22
A = n.2n+1 - (23 + 24 + 25 + ... + 2n) - 23
Đặt B = 23 + 24 + ... + 2n
2B = 24 + 25 + ... + 2n+1
2B - B = 24 + 25 + ... + 2n+1 - 23 - 24 - 2n
B = 2n+1 - 23
Mà A = n.2n+1 - (23 + 24 + 25 + ... + 2n) - 23
=> A = n.2n+1 - B - 23
=> A = n.2n+1 - (2n+1 - 23) - 23
A = n.2n+1 - 2n+1 + 23 - 23
A = (n-1).2n+1
Mà 2.22+ 3.23 + 4.24 + 5.25 + · · · + n.2n = 2n+10
=> A = 2n+10
=> (n-1).2n+1 = 2n+10
(n-1) = 2n+10 : 2n+1
n-1 = 29
n = 512 + 1
n = 513
đặt A=2.22+3.23+....+n*2n
2A=2.23+3.24+...+n.2n+1
=>A-2A=2.22+(3.23-2.23)+(4.24-3.24)+...+(n-n+1).2n-n.2n+1
=>A=2.22+23+...+2n-n.2n+1=22+(22+23+...+2n+1)-(n+1)2n+1
=>A=-22-(22+23+...+2n+1)+(n+1)2n+1
đặt B=22+23+...+2n+1=>2B=23+...+2n+1=>2B-B=2n+2-22
=>B=2n+2-22
vậy A=22-2n+2+22+(n+1)2n+1=(n+1)2n+1-2n+2=2n+1(n+1-2)=(n-1)2n+1=2(n-1)2n
theo bài cho A=2(n-1)2n=2n+10=>2(n-1)=210=>n-1=29=512=>n=513
vậy n=513