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24 = 23.3; 60 = 22.3.5
ƯCLN(24; 60) = 22.3 = 12
35 = 5.7; 7 = 7
ƯCLN(35; 7) = 7
24 = 23.3; 23 = 23
ƯCLN(24; 23) =1
35 = 5.7
7 = 7
1 =1
ƯCLN(35; 7; 1) =1
24 = 2³.3
60 = 2².3.5
⇒ ƯCLN(24; 60) = 2².3 = 12
⇒ ƯC(24; 60) = Ư(12) = {1; 2; 3; 4; 6; 12}
Ta có 24 = 23 x 3 ; 60 = 22 x 3 x 5 => ƯCLN(24;60)=22 x 3=12
=> ƯCLN(24;60) ∈ ƯC(12)∈{1;2;3;4;6;12}
a)1=1
8=2^3
=>UCLN(1;8)=1
b)8=2^3
1=1
12=2^2x3
=>UCLN(8;1;12)=1
c)24=2^3x3
72=2^3x3^2
=>UCLN(24;72)=2^3x3=24
d)24=2^3x3
84=2^2x3x7
180=2^2x3^2x5
=>UCLN(24;84;180)=2^2x3=12
1)
a) 18 = 2.3²
30 = 2.3.5
ƯCLN(18; 30) = 2.3 = 6
b) 24 = 2³.3
48 = 2⁴.3
ƯCLN(24; 48) = 2³.3 = 24
c) 18 = 2.3²
30 = 2.3.5
15 = 3.5
ƯCLN(18; 30; 15) = 3
d) 24 = 2³.3
48 = 2⁴.3
36 = 2².3²
ƯCLN(24; 48; 36) = 2².3 = 12
2) a) 174 = 18 . 9 + 12
18 = 12 . 1 + 6
12 = 6 . 2
Vậy ƯCLN(174; 18) = 6
b) 124 = 16 . 7 + 12
16 = 12 . 1 + 4
12 = 4 . 3
⇒ ƯCLN(124; 16) = 4
⇒ BCNN(124; 16) = 124 . 16 : 4 = 496
a) ƯCLN ( 16, 24 )
16 = 23 24 = 22.3
ƯCLN ( 16;24 ) = 22= 4
b) ƯCLN ( 60, 90 )
60 = 22.3.5 90=2.32.5
ƯCLN ( 60;90 ) = 2.3.5 = 30
c) ƯCLN ( 24, 84 )
24 = 23.3 84 = 22.3.7
ƯCLN ( 24;84 ) = 22.3 = 12
d) ƯCLN ( 16, 60 )
16 = 24 60 = 22.3.5
ƯCLN ( 16;60 ) = 22=4
e) ƯCLN ( 18, 77 )
18 = 2.32 77=7.11
ƯCLN ( 18; 77 ) = 1
g) ƯCLN ( 18, 90 )
18 = 2.32 90=2.32.5
ƯCLN ( 18;90 ) = 2.32 = 18
h) ƯCLN ( 18, 30, 42 )
18 = 2.32 30 = 2.3.5 42 = 2.3.7
ƯCLN ( 18;30;42 ) = 2.3=6
k) ƯCLN ( 26, 39, 48 )
26 = 2.13 39 = 3.13 48 = 24.3
ƯCLN ( 26;39;48 ) = 1
a. ƯCLN(420; 700) = 140
b. ƯCLN(13; 20) = 1
c. ƯCLN(16; 24) = 8
d. ƯCLN(60; 90; 135) = 15
\(a,420=2^2\cdot3\cdot5\cdot7;700=2^2\cdot5^2\cdot7\\ ƯCLN\left(420,700\right)=2^2\cdot5\cdot7=140\\ b,13=13;20=2^2\cdot5\\ ƯCLN\left(13,20\right)=1\\ c,16=2^4;24=2^3\cdot3\\ ƯCLN\left(16,24\right)=2^3=8\\ d,60=2^2\cdot3\cdot5;90=2\cdot3^2\cdot5;135=3^3\cdot5\\ ƯCLN\left(60,90,135\right)=3\cdot5=15\)
a)Ta thấy: 24=23.3 , 60=22.3.5
=>ƯCLN(24,60)=22.3=12
b)Ta thấy: 35=5.7 , 7=7
=>ƯCLN(35,7)=7
c)Ta thấy: 24=23.3 , 23=1
=>ƯCLN(24,23)=1
d)Ta thấy: 35=5.7 , 7=7 , 1=1
=>ƯCLN(35,7,1)=1