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a, \(\left(x^2-9\right)^2-\left(x-3\right)\left(x+3\right)\left(x^2+9\right)=\left(x^2-9\right)^2-\left(x^2-9\right)\left(x^2+9\right)\)
\(=x^4-18x^2+81-x^4+81=-18x^2+162\)
b, \(\left(x^2+x-3\right)\left(x^2-x+3\right)=\left[x^4-\left(x-3\right)^2\right]\)
\(=x^4-x^2+6x-9\)
\(\dfrac{3-3x}{\left(1+x\right)^2}:\dfrac{6x^2-6}{x+1}\)
\(=\dfrac{3\left(1-x\right)}{\left(x+1\right)^2}:\dfrac{6\left(x^2-1\right)}{x+1}\)
\(=\dfrac{-3\left(x-1\right)}{\left(x+1\right)^2}:\dfrac{6\left(x+1\right)\left(x-1\right)}{x+1}\)
\(=\dfrac{-3\left(x-1\right)}{\left(x+1\right)^2}\cdot\dfrac{x+1}{6\left(x+1\right)\left(x-1\right)}\)
\(=\dfrac{-3\left(x-1\right)\left(x+1\right)}{6\left(x+1\right)^3\left(x-1\right)}=\dfrac{-3\left(x+1\right)}{6\left(x+1\right)\left(x+1\right)^2}=\dfrac{-3}{6\left(x+1\right)^2}=\dfrac{-1}{2\left(x+1\right)^2}\)
b) Bạn có thể viết kiểu latex được không ạ ?
\(a,\left(3x+x\right)\left(x^2-9\right)-\left(x-3\right)\left(x^2+3x+9\right)\)
\(=4x\left(x^2-9\right)-x^3+27\)
\(=4x^3-36x-x^3+27\)
\(=3x^3-36x+27\)
\(\left(x+6\right)^2-2x.\left(x+6\right)+\left(x-6\right).\left(x+6\right)\)
\(=\left(x+6\right).\left(x+6-2x+x-6\right)\)
\(=\left(x+6\right).0\)
\(=0\)
làm như bình thường là đc:
a) ( x + 2 )^3 - x^2 . ( x+ 6 ) - 8
= ( x^3 + 3.x^2.2 +3.x.2^2 + 2^3 ) - ( x^3 + 6x^2 ) - 8
= x^3 + 6x^2 + 12x + 8 - x^3 - 6x^2 - 8
=12x
b) ( x - 2 ) . ( x^2 + 2x + 4 ) - ( x^3 + 2 )
= x^3 - 2^3 - ( x^3 + 2 )
= x^3 - 8 - x^3 - 2
= -6
\(A=4x^2+12xy+9y^2\)
\(B=25x^2-10xy+y^2\)
\(C=8x^3+12x^2y^2+6xy^4+y^6\)
\(D=\left(x^2\right)^2-\left(\dfrac{2}{5}y\right)^2=x^4-\dfrac{4y^2}{25}\)
\(E=x^3-27y^3\)
\(F=x^6-27\)
`th1:`
`(x+1)(x^2-x+1):(x-3)(x^2+3x+9)`
`=(x^3+1^3):(x^3-3^3)`
`=(x^3+1):(x^3-27)`
`=(x^3+1)/(x^3-27)`
`=(x^3-27+28)/(x^3-27)`
`=1+28/(x^3-27)`
`**th2:`
`(x+1)(x^2-x+1)`
`=x^3+1^3=x^3+1`
`(x-3)(x^2+3x+9)`
`=x^3-3^3=x^3-27`
Minh xin loi ban nhe , ban sua lai giup minh cho x3 - 9 thanh x3 - 27
\(\left(x^2-9\right)^2-\left(x+3\right)\left(x-3\right)\left(x^2+9\right)=x^4-18x^2+81-\left(x^2-9\right)\left(x^2+9\right)=x^4-18x^2+81-\left(x^4-81\right)=x^4-18x^2+81-x^4+81=-18x^2+162=-18\left(x^2-9\right)=-18\left(x-3\right)\left(x+3\right)\)