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\(=\frac{3^6.3^8.5^4-3^{13}.5^{13}.\frac{1}{5^9}}{3^{12}.5^6+3^{12}.5^6}\)
\(=\frac{3^{13}.5^4\left(3-1\right)}{3^{12}.5^6.2}\)
\(=\frac{3}{5^2}=\frac{3}{25}\)
a)\(\frac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}=\frac{3^6.\left(3^2.5\right)^4-\left(3.5\right)^{13}.5^{-9}}{\left(3^3\right)^4.\left(5^2\right)^3+\left(3^2.5\right)^6}=\frac{3^6.3^8.5^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)
\(=\frac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6+3^{12}.5^6}=\frac{3^{13}.5^4.\left(3-1\right)}{3^{12}.5^6\left(1+1\right)}=\frac{3^{13}.5^4}{3^{12}.5^6}=\frac{3}{5^2}=\frac{3}{25}\)
b)\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}-6^{11}}=\frac{\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5}{-\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2^{12}.3^{10}+2^9.3^9.2^3.3.5}{-2^{12}.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{-2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.3^{10}+2^{12}.3^{10}.5}{-\left(2^{12}.3^{12}+2^{11}.3^{11}\right)}=\frac{2^{12}.3^{10}\left(1+5\right)}{-\left[2^{11}.3^{11}\left(2.3+1\right)\right]}=\frac{2.6}{-\left(3.7\right)}=\frac{4}{-7}\)
a) Tử số = 3^6.45^4−15^13.5^−9=3^6.(5.3^2)^4−(3.5)^13.5^−9=3^6.5^4.3^8−3^13.5^13.5^−9=3^14.5^4−3^13.5^4=3^13.5^4(3−1)=2.3^13.5^4
Mẫu số = 27^4.25^3+45^6=3^12.5^6+3^12.5^6=2.3^12.5^6
Phân số = 2.3^13.5^4/2.3^12.5^6=3/25
\(\frac{3^6.45^4-15^{13}:5^9}{27^4.25^3+45^6}\)=\(\frac{3^{14}.5^4-3^{13}.5^4}{3^{12}.5^6+3^{12}.5^6}=\frac{3^{13}.5^4\left(3-1\right)}{3^{12}.5^6\left(1+1\right)}\)=\(\frac{3}{25}\)
\(\frac{3^6.3^8.5^4-3^{13}.5^{13}:5^9}{3^{12}.5^6+3^{12}.5^6}=\frac{3^{14}.5^4-3^{13}.5^4}{2.3^{12}.5^6}=\frac{2.3^{13}.5^4}{2.3^{12}.5^6}=\frac{1}{75}\)
\(\dfrac{3^6.45^4-15^{13}.5^{-9}}{27^4.25^3+45^6}=\dfrac{3^6.3^85^4-3^{13}.5^{13}.5^{-9}}{3^{12}.5^6+3^{12}.5^6}\)
\(=\dfrac{3^{14}.5^4-3^{13}.5^4}{2.3^{12}.5^6}=\dfrac{3^{13}.5^4\left(3-1\right)}{2.3^{12}.5^6}\)
\(=\dfrac{3.2}{2.5^2}=\dfrac{3}{25}\)
\(\frac{3^6\times45^4-15^{13}\times5^{-9}}{27^4\times25^3+45^6}\)
= \(\frac{3^6\times\left(3^2\right)^6\times5^6-3^{13}\times5^{13}\times5^{-9}}{3^{12}\times5^6+\left(3^2\right)^6\times5^6}\)
= \(\frac{3^6\times3^{12}\times5^6-3^{13}\times5^4}{3^{12}\times5^6\times\left(1+1\right)}\)
= \(\frac{3^{13}\times5^4\times\left(3^5\times5^2-1\right)}{3^{12}\times5^6\times2}\)
= \(\frac{3\times\left(3^5\times5^2-1\right)}{5^2\times2}=\frac{3^6\times3\times5^2-3}{5^2\times2}\)
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