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\(a,5^{n+1}-4.5^n=5^n\left(5-4\right)=5^n\)
B2:
\(4\left(18-5x\right)-12.\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow156-56x-24x+324=0\)
\(\Rightarrow480-80x=0\)
\(\Rightarrow80x=480\)
\(\Rightarrow x=6\)
Vậy x=6
Bài 1:
\(a,5^{n+1}-4.5^n=5^n\left(5-4\right)\)
\(=5^n.1\)
\(=5^n\)
\(b,6^2.6^4-4^3.\left(3^6-1\right)=6^6-\left(2^2\right)^3\left(3^6-1\right)\)
\(=6^6-2^6\left(3^6-1\right)\)
\(=6^6-6^6+2^6\)
\(=2^6\)
\(=64\)
Bài 2:
\(a,4.\left(18-5x\right)-12.\left(3x-7\right)=15.\left(2x-16\right)-6.\left(x+14\right)\)
\(\Rightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Rightarrow30x-6x+20x+36x=72+84+240+84\)
\(\Rightarrow80x=6372\)
\(\Rightarrow x=79,65\)
\(\dfrac{3-3x}{\left(1+x\right)^2}:\dfrac{6x^2-6}{x+1}\)
\(=\dfrac{3\left(1-x\right)}{\left(x+1\right)^2}:\dfrac{6\left(x^2-1\right)}{x+1}\)
\(=\dfrac{-3\left(x-1\right)}{\left(x+1\right)^2}:\dfrac{6\left(x+1\right)\left(x-1\right)}{x+1}\)
\(=\dfrac{-3\left(x-1\right)}{\left(x+1\right)^2}\cdot\dfrac{x+1}{6\left(x+1\right)\left(x-1\right)}\)
\(=\dfrac{-3\left(x-1\right)\left(x+1\right)}{6\left(x+1\right)^3\left(x-1\right)}=\dfrac{-3\left(x+1\right)}{6\left(x+1\right)\left(x+1\right)^2}=\dfrac{-3}{6\left(x+1\right)^2}=\dfrac{-1}{2\left(x+1\right)^2}\)
b) Bạn có thể viết kiểu latex được không ạ ?
Thực hiện phép tính a. 3 5 6. 5 3 5b. 4 3 2.9 4 6 7.8 2c. 4 3 2. 3 4 4 3 2 6
Bài 1:
\(3a.\left(2a^2-ab\right)=6a^3-3a^2b\)
\(\left(4-7b^2\right).\left(2a+5b\right)=8a+20b-14ab^2-35b^3\)
Bài 2:
\(2x^2-6x+xy-3y=2x.\left(x-3\right)+y.\left(x-3\right)=\left(x-3\right).\left(2x+y\right)\)
Bài 3: Tại x = 3/2, y =1/3 thì Q = 67/9
Bài 4:
\(\left(\frac{1}{x+1}+\frac{2x}{1-x^2}\right).\left(\frac{1}{x-1}\right)\) \(\frac{1}{\left(x+1\right).\left(x-1\right)}+\frac{2x}{\left(1-x^2\right).\left(x-1\right)}=\frac{x-1}{\left(x+1\right).\left(x-1\right)^2}+\frac{-2x}{\left(x-1\right)^2.\left(x+1\right)}\)
= \(\frac{x-1-2x}{\left(x+1\right).\left(x-1\right)^2}=\frac{-\left(x+1\right)}{\left(x+1\right).\left(x-1\right)^2}=\frac{-1}{\left(x-1\right)^2}\)
1.(2x+3).(x-5)+2x(3-x)+x-10
=2x^2 -10x+3x-15+6x-2x^2+x-10
=2x-25
2.(-x-2)3+(2x-4).(x2+2x+4)-x2.(x-6)
=-x^3+6x^2-12x-8+2x^3+4x^2+8x-4x^2+8x-16-x^3+6x^2
kcj ^^
\(6^2\times6^4-4^3\times\left(3^6-1\right)=6^6-\left(2^2\right)^3\times\left(3^6-1\right)=\left(2\times3\right)^6-2^6\times\left(3^6-1\right)=2^6\times3^6-2^6\times3^6+2^6=64\)