Question

[nguyễn hoàng khải phong]

thực hiện các phép tính

a.\(\frac{5z+10}{4x-8}.\frac{4-2x}{x+2}\)

b.\(\frac{1-4x^2}{x^2+4x}:\frac{2-4x}{3x}\)

Answer 1

[Ngô Vũ Quỳnh Dao]

a) \(\frac{5x+10}{4x-8}.\frac{4-2x}{x+2}=\frac{5\left(x+2\right)}{4\left(x-2\right)}.\frac{2\left(2-x\right)}{x+2}=\frac{-5}{2}\)

b) \(\frac{1-4x^2}{x^2+4x}:\frac{2-4x}{3x}=\frac{\left(1-2x\right)\left(1+2x\right)}{x\left(x+4\right)}.\frac{3x}{2\left(1-2x\right)}=\frac{3\left(1+2x\right)}{2\left(x+4\right)}=\frac{3+6x}{2x+8}\)