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ta có \(\frac{22}{7}=\frac{242}{77}\)
\(\frac{34}{11}=\frac{238}{77}\)
mà 242>238
\(\Rightarrow\frac{22}{7}>\frac{34}{11}\)
nhớ tk nha bạn
Ta có :
22/7=242/77
34/11=238/77
vì 242>238
=> 242/77>238/77
=>22/7>34/11
a) Ta có: \( - 2 = \frac{{ - 2}}{1} = \frac{{ - 40}}{{20}}\)
\(\frac{{ - 11}}{5} = \frac{{ - 44}}{{20}} < \frac{{ - 40}}{{20}}\) nên \(\frac{{ - 11}}{5} < -2\).
\(\frac{{ - 7}}{4} = \frac{{ - 7.5}}{{4.5}} = \frac{{ - 35}}{{20}} > \frac{{ - 40}}{{20}}\) nên \(\frac{{ - 7}}{4} > -2\)
Vậy \(\frac{{ - 11}}{5} < \frac{{ - 7}}{4}\).
b) Ta có: \(\frac{{2020}}{{ - 2021}} = \frac{{ - 2020}}{{2021}} > \frac{{ - 2022}}{{2021}}\)
Vậy \(\frac{{2020}}{{ - 2021}} > \frac{{ - 2022}}{{2021}}\)
a) \(\frac{34}{13}=2\frac{8}{13}\)
Vì 2 > 1 nên \(2\frac{8}{13}>1\frac{7}{9}\)
hay \(\frac{34}{13}>1\frac{7}{9}\)
b) \(\frac{7}{9}=1-\frac{2}{9}\)
\(\frac{13}{15}=1-\frac{2}{15}\)
Vì \(\frac{2}{9}>\frac{2}{15}\) nên \(\frac{7}{9}< \frac{13}{15}\)
a) Ta có:
\(1\frac{7}{9}=\frac{16}{9}=\frac{208}{117}\)
\(\frac{34}{13}=\frac{306}{117}\)
Vì \(306>208\)
\(\Rightarrow\frac{306}{117}>\frac{208}{117}\)
\(\Rightarrow\frac{34}{13}>1\frac{7}{9}\)
b) Ta có:
\(\frac{7}{9}=\frac{35}{45}\)
\(\frac{13}{15}=\frac{39}{45}\)
Vì \(39>35\)
\(\Rightarrow\frac{39}{45}>\frac{35}{45}\)
\(\Rightarrow\frac{13}{15}>\frac{7}{9}\)
a,\(\frac{11}{53}=\frac{22}{106}< \frac{22}{37}\)
b,\(\frac{13}{25}=\frac{52}{100}< \frac{53}{100}\)
\(\frac{22}{45}\)< \(\frac{51}{101}\)
\(\frac{23}{48}\)< \(\frac{47}{92}\)
\(\frac{34}{43}\)< \(\frac{35}{42}\)
\(A=\left(-\frac{1}{2013}-\frac{3}{11^2}-\frac{5}{11^3}-\frac{3}{11^4}\right)-\frac{4}{11^4};B=\left(-\frac{1}{2013}-\frac{3}{11^2}-\frac{5}{11^3}-\frac{3}{11^2}\right)-\frac{4}{11^2}\)
Vì 114 > 112 nên \(\frac{4}{11^4}-\frac{4}{11^2}\) => A > B
22/7>34/11
= \(\frac{242}{77}\) < \(\frac{283}{77}\)
VẬY ĐIÊN DẤU <